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1 year ago

Choose the values that would complete the general solution for y= arctan (0.7002).

Mathematics

1 answer:

e-lub [12.9K]1 year ago

6 0

Answer:

-145°, -325°

Step-by-step explanation:

The principal value of the arctangent of 0.7002 is 35°. The tangent function is periodic with a period of 180°, so the general solution is ...

y = (35 +180k) degrees . . . . . where k is an integer

Values from the given list include ...

-145°

-325°

_____

Additional comment

+35° and +215° would also be part of the general solution

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Igoryamba

Answer:

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Step-by-step explanation:

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2 years ago

Perimeter=42 meters what is the length

Dominik [7]

4a= 42
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3 years ago

The figure represents a(n) ______. A. angle B. line segment C. ray D. line

anygoal [31]

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7 0

3 years ago

Read 2 more answers

rusak2 [61]

Answer:

(1.13, 7.74) and (-4.13, 18.26)

Step-by-step explanation:

This can be solved in two ways: mathematically and graphically.

Graphing

Plot both lines and find where they intersect. See the attachment.

The intersection points are (1.13, 7.74) and (-4.13, 18.26)

Mathematical

y + 2x = 10

y = 10 - 2x

y = 3x² + 7x - 4

10 - 2x = 3x² + 7x - 4

3x² + 9x - 14 = 0

Solve this using the quadratic equation:

x = 1.13 and -4.13

Use these two values of x to find y:

y = 10 - 2x

y = 10 - 2(1.13)

y = 7.74

y = 10 -2x

y = 10 -2(-4.13)

y = 18.26

The two points are:

(1.13, 7.74) and (-4.13, 18.26)

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2 years ago

−2x=x^2 minus 6, Rewrite the equation by completing the square. please answer

Paul [167]

Answer:

$(x+1)^{2} -5$

Step-by-step explanation:

$-2x=x^{2} -6 \\x^{2} +2x-6\\(\frac{b}{2}) ^{2} =(\frac{2}{2}) ^{2} =1^{2} =1\\so, (x^{2} +2x+1)-6+1\\ x^{2} +2x+1=(x+1)^{2} \\-6+1=5\\(x+1)^{2} -5$

Sorry it took so long

4 0

3 years ago