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user100 [1]
4 years ago
15

Kinkead Inc. forecasts that its free cash flow in the coming year, i.e., at t = 1, will be -$10 million, but its FCF at t = 2 wi

ll be $20 million. After Year 2, FCF is expected to grow at a constant rate of 4% forever. If the weighted average cost of capital is 14%, what is the firm's value of operations, in millions?
Select one:
a. $158
b. $167
c. $175
d. $184
e. $193
Business
1 answer:
Gwar [14]4 years ago
3 0

Answer:

correct option is b. $167

Explanation:

given data

free cash flow FCF 1 = -$10 million

t = 1

free cash flow FCF 2= $20 million

t = 2

FCF grow rate = 4%

average cost of capital = 14%

to find out

what is the firm's value of operations

solution

first we get here firm value in year 2 that is express as

firm value in year 2 = expected FCF in 3 ÷ (cost of capital - growth)    .........1

put here value

firm value in year 2 = \frac{20*(1+0.04)}{0.14 - 0.04}

firm value in year 2 = 208 million

and

firm value of operation this year will be as

firm value = discounted value in year 2 + discounted FCF1 and FCF2     .............2

firm value = \frac{208}{(1+0.14)^2} +\frac{20}{(1+0.14)^2} +\frac{-10}{(1+0.14)}

firm value = 166.67 = 167 million

so correct option is b. $167

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Answer:

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Who of the following is not included in the Bureau of Labor Statistics' "employed" category?
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Answer:

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Explanation:

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Consider the following data set:
Andrei [34K]

Answer:

Kindly check explanation

Explanation:

To obtain the mean absolute deviation(MAD) :

Subtract the forecasted values from the actual values and find its absolute equivalent.

Error (E) = (Actual - forecast)

e1 - - - |e1| - - - - e2 - - - |e2| - APE1 - - APE2

6 - - - - 6 - - - - - 8 - - - - 8 - - 0.772 - - - 1.030

4 - - - - 4 - - - - - 2 - - - - 2 - - 0.507 - - 0.253

4 - - - - 4 - - - - - 2 - - - - 2 - - 0.504 - - 0.252

(-4) - - - 4 - - - - - (-18) - - 18 - 0.513 - - 2.308

(-2) - - - 2 - - - - (-6) - - - 6 - - 0.260 - - 0.781

11 - - - - 11 - - - - 9 - - - - 9 - - 1.412 - - - 1.155

(-1) - - - 1 - - - - - 1 - - - - 1 - - - 0.132 - - 0.132

14 - - - 14 - - - - 10 - - - 10 - - 1.783 - - 1.274

2 - - - - 2 - - - - (-2) - - 2 - - - 0.254 - - 0.254

3 - - - - 3 - - - - - 3 - - - 3 - - 0.379 - - - 0.379

MAD for forecast 1:

(Sum of |e1|) / number of observation

(6 + 4 + 4 + 4 + 2 + 11 + 1 + 14 + 2 + 3) / 10

= 51 / 10

= 5.1

MAD for forecast 2:

(Sum of |e2|) / number of observation

(8 + 2 + 2 + 18 + 6 + 9 + 1 + 10 + 2 + 3) / 10

61 / 10

= 6.1

MAPE = (Sum of absolute percentage error) / number of observations

Forecast 1:

(0.772 + 0.507 + 0.504 + 0.513 + 0.260 + 1.412 + 0.132 + 1.783 + 0.254 + 0.379)% / 10

= 6.516% / 10 = 0.6516%

MAPE Forecast 2:

(1.030 + 0.253 + 0.252 + 2.308 + 0.781 + 1.155 + 0.132 + 1.274 + 0.254 + 0.379)% / 10

= 7.818% / 10

= 0.7818%

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