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2 years ago

What is 75 times .25?

Mathematics

2 answers:

finlep [7]2 years ago

8 0

75 x 0.25 = 18.75 have a great day :D

LuckyWell [14K]2 years ago

4 0

The answer to the question is 18.75

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HelloI need some assistance with this question. I provided an answer, but it was incorrect. The images are enclosed.

ycow [4]

Given:

There are given that the zeroes and degrees of the polynomial:

$\begin{gathered} \text{zeros:}-2,2,4 \\ \text{Degres:}3 \end{gathered}$

Explanation:

From the concept of a polynomial:

A polynomial has a as zero if and only if (x -a) is a factor of the polynomial.

Then,

From the given polynomial:

$f(x)=(x+2)(x-2)(x-4)$

Then,

$\begin{gathered} f(x)=(x+2)(x-2)(x-4) \\ f(x)=(x^2-2x+2x-4)(x-4) \\ f(x)=(x^2-4)(x-4) \\ f(x)=x^3-4x^2-4x+16 \end{gathered}$

Final answer:

Hence, the polynomial is shown below:

$f(x)=x^3-4x^2-4x+16$

6 0

1 year ago

If you can score 54 points in 6 minutes, how many points are you scoring in one minute? please help all my points.

Bess [88]

Answer:

Step-by-step explanation:

54 / 6= 9

9 points per minute

8 0

2 years ago

Read 2 more answers

You own an accessories store, and sales last month were $24,000. You had $3,500 in discounts and $975 in returns.

Len [333]

Answer:

The net sales for last month were $19,525.

Step-by-step explanation:

Given:

Last month sales were $24,000.

Discounts is $3,500 and $975 in returns.

Now, to get the net sales for last month.

So, we deduct the discount:

Sales - discounts = $\$24,000 - \$3,500 =\$20,500.$

Then, we deduct the returns from the remaining amount:

Sales after discounts - returns = $\$20,500 - \$975$

= $\$19,525.$

Therefore, the net sales for last month were $19,525.

7 0

2 years ago

Susan threw a softball 42 years on her first try and 51 1/3 yard on her second try. How much farther did she throw the softball

Andru [333]

Answer:

28 feet farther than 1st ball.

Step-by-step explanation:

We have been given that Susan threw a softball 42 yards on her first try and $51\frac{1}{3}$ yard on her second try.

To find second ball is how much farther from the 1st ball, we will subtract 42 yards from $51\frac{1}{3}$ yards.

$\text{The second ball is farther from 1st ball}=51\frac{1}{3}\text{ yards}-42\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-42\text{ yards}$

Let us have a common denominator.

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{42*3}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{126}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154-126}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{28}{3}\text{ yards}$

$\text{1 yard}=3\text{ feet}$

$\frac{28}{3}\text{ yards}=\frac{28}{3}\times 3\text{ feet}$

$\frac{28}{3}\text{ yards}=28\text{ feet}$

Therefore, Susan thrown the second ball 28 feet farther from the 1st ball.

7 0

3 years ago

Name the edges of an hexagonal pyramid

aleksandrvk [35]

Given:

Hexagonal pyramid

To find:

The edges of an hexagonal pyramid.

Solution:

Edges means lines which connecting to vertices.

Edges in the base of the pyramid:

AB, BC, CD, DE, EF, FA

Edges in the triangular shape of the pyramid:

AG, BG, CG, DG, EG, FG

Therefore edges of an hexagonal pyramid are:

AB, BC, CD, DE, EF, FA, AG, BG, CG, DG, EG, FG

4 0

3 years ago