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2 years ago

I know I put An answer I don’t know if that’s it I just accidentally put it

Mathematics

2 answers:

Y_Kistochka [10]2 years ago

7 0

Answer:

the answer is 36ft² or c

Step-by-step explanation:

hope this helps :)

balu736 [363]2 years ago

5 0

Answer:

Step-by-step explanation:

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Given the triangle below, which of the following is a correct statement? Right triangle ABC with AB measuring 5, AC measuring 6,

Elanso [62]

Drawing a diagram to match this figure, BC would have to be the hypotenuse as it is the longest side of the triangle. Angle A would have to be the right angle.
For the first choice, $\cot B = \frac{1}{ \tan B} 
\\ = \frac {1}{\frac {6}{5}}
\\ = 1 \div \frac{6}{5} = \frac{1}{1} \div \frac{6}{5}
\\ = \frac{1}{1} * \frac{5}{6} = \frac{5}{6}$ . The first choice is not correct.
The second choice gives us $\csc C= \frac{1}{ \sin C}= \frac{1}{\frac {5}{8}}
\\ = 1 \div \frac{5}{8} = \frac{1}{1} \div \frac{5}{8}
\\ = \frac{1}{1} * \frac{8}{5} = \frac{8}{5}$ . The second choice is not correct either.
The third choice gives us

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3 years ago

Can you guys help me!!!! Question 3

Makovka662 [10]

Answer:

F = ( 9/5) X c + 32

Step-by-step explanation:

5 0

2 years ago

Y = x2 - 2x + 1<br> Solve the equation algebraically

Leviafan [203]

Just factor. y = (x-1)(x-1)

5 0

2 years ago

How do you know if AB and CD are congruent?

Mariana [72]

If the length of two segments is equal then the two segments are congruent.

If l(AB) = l(CD) then seg AB ≅ seg CD.

Two line segments to be congruent if and only if they have the same length.

Two shapes are congruent if they are exactly the same shape and exactly the same size. In congruent shapes, all corresponding sides will be the same length and all corresponding angle will be the same measure.

To know more about congruent here

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6 months ago

Solve the equation in the complex number system. x^2-12x+40=0

mylen [45]

solving the equation $x^2-12x+40=0$ we get $x=6+2i\,\,and\,\,x=6-2i$

Step-by-step explanation:

Solve the equation:

$x^2-12x+40=0$

We can solve using quadratic Formula:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

a= 1, b = -12, c = 40

Putting values:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-12)\pm\sqrt{(-12)^2-4(1)(40)}}{2(1)}\\x=\frac{12\pm\sqrt{144-160}}{2}\\x=\frac{12\pm\sqrt{-16}}{2}\\We\,\,know\,\,\sqrt{-1}=i\\ x=\frac{12\pm4i}{2}\\ x=\frac{12+4i}{2}\,\,and\,\, x=\frac{12-4i}{2}\\ x=\frac{4(3+i)}{2}\,\,and\,\, x=\frac{4(3-i)}{2}\\x=2(3+i)\,\,and\,\,x=2(3-i)\\x=6+2i\,\,and\,\,x=6-2i$

So, solving the equation $x^2-12x+40=0$ we get $x=6+2i\,\,and\,\,x=6-2i$

Keywords: Solving quadratic equation

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3 years ago