<span>−13b=9
divide both sides by -13
</span><span>−13b/-13 =9/-13
simplify
b = -9/13</span>
<span>Simplifying
3x + 6 = 2x
Reorder the terms:
6 + 3x = 2x
Solving
6 + 3x = 2x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-2x' to each side of the equation.
6 + 3x + -2x = 2x + -2x
Combine like terms: 3x + -2x = 1x
6 + 1x = 2x + -2x
Combine like terms: 2x + -2x = 0
6 + 1x = 0
Add '-6' to each side of the equation.
6 + -6 + 1x = 0 + -6
Combine like terms: 6 + -6 = 0
0 + 1x = 0 + -6
1x = 0 + -6
Combine like terms: 0 + -6 = -6
1x = -6
Divide each side by '1'.
x = -6
Simplifying
x = -6
</span>so the answer is x =-6
According to http://www.geteasysolution.com/3x+6=2x
If you would like to know how much farther does Louisa's family need to drive, you can calculate this using the following steps:
791 miles - 114 miles = 677 miles ... 700 miles
The correct result would be D. 700 mi.
Answer:
1.) The product of 12 and 3/4 is less than 12. This is because you are multiplying 12 by a number less than 1.
2.) The product of 5 and 1/2 is less than 5, this is because you are multiplying 5 by a number less than one.
Step-by-step explanation:
If multiplied by a number less than one then it will be smaller than original
If multiplied by one will be the same as original
If multiplied by a number greater than one it will be greater than original
Answer:
The product is:
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D15%20%26%2014%5C%5C-1%20%26%209%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:
![\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%261%5C%5C-2%261%260%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-2%5C%5C3%265%5C%5C4%261%5Cend%7Barray%7D%5Cright%5D)

So the value of the element in the position
is 15

So the value of the element in the position
is 14
Then with these two values you can determinate the result matrix.
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D15%20%26%2014%5C%5C-1%20%26%209%5Cend%7Barray%7D%5Cright%5D)