Three times the 1st number plus the 2nd number plus twice the 3rd is 5 is the same as 3x+y+2z=5. If three times the 2nd number is subtracted from the sum of the 1st and three times the 3rd number, the result is 2 is just x+3z-3y=2. And if the 3rd number is subtracted from two times the 1st number and three times the 2nd, giving a result of 1 means 2x+3y-z=1. Then you use substition on these equations to get a equation where one variable equals 2 others, like using the first to get y=5-2z-3x and then this can be substituted into the other two to get x+3z-3(5-2z-3x)=2 and 2x+3(5-2z-3x)-z=1 we can then simplify and subtract the equations. After simplification we have 10x+9z=17 and 7z+7x=16 which can be turned into 70x+63z=119 and 70x+70z=160 which can be then subtracted to get that 7z=41 and z=41/7. Now we backtrack to a two variable equation like 7z+7x=16 and plug in to find x. So after plugging in we get 41+7x=16 and 7x=-25 so x=-25/7. Now we choose a 3 variable equation and plug in. So taking y=5-2z-3x we plug in 41/7 for z and -25/7 for x to get y=5-82/7+75/7 and y=5-7/7 and y=4. Therefore x = -25/7 y = 4 and z = 41/7.
Answer:
y = -1/4x^2 - x + 3
Step-by-step explanation:
(-6,0)
(-4,3)
(2,0)
36a - 6b + c = 0
16a -4b + c = 3
4a + 2b + c = 0
c = -4a - 2b
36a - 6b - 4a -2b = 0
16a - 4b -4a - 2b = 3
32a -8b = 0
12a - 6b = 3
4a - b = 0
4a - 2b = 1
b = -1
4a + 1 = 0
4a = -1
a = -1/4
c = 1 + 2 = 3
y = -1/4x^2 - x + 3
I believe the term is a "radical"
Hope this helps!
