Bryan was given the equation y= -5x+3. He says the rate of change is 3 and the initial value is -5. Is Bryan correct? If not, co
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Given equation : y=5/2x.
Solution: In order to graph direct variation equation, we need to make a table of different values of x and y.
We need to plug some values of x's in equation to get values of y's.
Because, we have fraction 5/2, and 2 in denominator. So it would be better to take multiples of 2, so that we don't get values in decimals.
Let us take x=0 first.
Plugging x=0 in given equation, we get
y=5/2x = 5/2(0) = 0.
Let us take x=2 first.
Plugging x=2 in given equation, we get
y=5/2 *(2) = 5
Let us take x=2 first.
Plugging x=4 in given equation, we get
y=5/2 *(4) = 5 *2 = 10.
We got three coordinates for the graph (0,0) , (2,5) and (4, 10).
Let us plot those coordinates on the graph and join the points to draw a straight line.
