Answer:
A. Eric rode 2 more miles per week than Kim rode
Step-by-step explanation:
Number of miles Kim rode bicycle in 9 weeks = 135 miles
Let x be the number of miles per week.
135miles => 9 weeks
x miles => 1 week
Kim rode the bicycle 15 miles per week
Number of miles Eric rode bicycle in 6 weeks = 102 miles
Let x be the number of miles per week Eric rides the bicycle.
102 miles => 6 weeks
x miles => 1 week
Kim rode the bicycle 17 miles per week
<em>Comparing the number of miles per week they rode, we would conclude that: "Eric rode 2 more miles per week than Kim rode".</em>
Answer:
(√9)^2x-1/2 = 1/81
3^2x-1/2 = 1/(3)⁴. (as √9 = 3)
3^2x-1/2 = 3^-⁴. (as 1/a^m = a^-m)
as base are equal exponents are equal
so 3 gets cancelled out
2x-1/2 = -4
(4x-1)/2 = -4
4x-1 = -8
x = -7/4
hope this helps
Step-by-step explanation:
There is one restriction: The number whose square root is needed can not be negative
Answer:
y²-2y+3
Step-by-step explanation:
We write the dividend, y³-y²+y+3, under the box and the divisor, y+1, to the left of the box.
We first divide y³ by y; this is y². We write this above the box, over -y². We multiply the divisor by y²:
y²(y+1) = y³+y²
This goes under the divisor. We then subtract:
(y³-y²)-(y³+y²) = -2y². We then bring down the next term, y; this gives us -2y²+y.
We then divide -2y² by y; this is -2y. This goes above the box beside the y² in the quotient. We then multiply the divisor by -2y:
-2y(y+1) = -2y²-2y
We now subtract:
(-2y²+y)-(-2y²-2y) = 3y. We bring down the last term, 3; this gives us 3y+3. We divide 3y by y; this is 3. This goes beside the -2y in the quotient. We then multiply this by the divisor:
3(y+1) = 3y+3. We then subtract: (3y+3)-(3y+3) = 0
This makes the quotient y²-2y+3.
Answer:
-0.05
Step-by-step explanation:
This will become much easier if we can get the ugly decimal into a nice fraction form.
Start by recognising 
. This is almost correct except the fraction is out by some number of factors of 10 (because the 125 part is correct but the number of 0s isn't).
And hence we see that 
and now the cube root becomes easy to compute:
![\sqrt[3]{-0.000125} = \sqrt[3]{\frac{-1}{8000}} = \frac{\sqrt[3]{-1}}{\sqrt[3]{8000}} = \frac{-1}{20} = -0.05](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-0.000125%7D%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B-1%7D%7B8000%7D%7D%20%3D%20%5Cfrac%7B%5Csqrt%5B3%5D%7B-1%7D%7D%7B%5Csqrt%5B3%5D%7B8000%7D%7D%20%3D%20%5Cfrac%7B-1%7D%7B20%7D%20%3D%20-0.05)
.
Advanced: You ask for <em>all </em>real cube roots. however the function ![y=\sqrt[3]{x}](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7Bx%7D)
is described as <em>bijective</em>. This means for all x, there is only one y corresponding to it. (And also for all y there is only one x corresponding to that). This means there can only ever be one cube root of any real number.
