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Alex17521 [72]
2 years ago
9

Please help me!! 20 pts!

Mathematics
1 answer:
choli [55]2 years ago
7 0

Answer:

blank 3, 30

Step-by-step explanation:

You might be interested in
Evaluate x+2.7 for x=-1.5
jonny [76]

Answer:

1.2

Step-by-step explanation:

First make -1.5 equal to 0.

We'll have to add 1.5, right?

So 1.5 is in 2.7.

So now its 0 + ? = ?

2.7 - 1.5 = 1.2

So 0 + 1.2 = 1.2

Hope this helped.

3 0
3 years ago
Given the triangle that has a base of five less than triple the height. The height is 2x+6.
Deffense [45]

Answer:

<h3>          A = 0.5(2x+6)(6x+13) = 6x² + 49x + 78</h3>

Step-by-step explanation:

H = 2x+6          - the hight

3H = 3(2x+6)      - triple the hight

3H-5 = 3(2x+6) - 5    -  five less than triple the height

Area of triangle:  A = 0.5BH

B = 3(2x+6)-5 = 6x + 18 - 5 = 6x + 13

H = 2x+6

So:

    A = 0.5(2x+6)(6x+13) = (x+6)(6x+13) = 6x² + 13x + 36x + 78

    A = 6x² + 49x + 78

5 0
2 years ago
Please please please help and solve this with steps, much help needed thank you :) 20 points for this!
leonid [27]

Answer:

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

\frac{dy}{dx}y=x^3+2x-5x+3

\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}

  • \mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)

1. \mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:

y'\:y=x^3+2x-5x+3

2. \mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}

yy'\:=x^3-3x+3

  • N\left(y\right)\cdot y'\:=M\left(x\right)
  • N\left(y\right)=y,\:\quad M\left(x\right)=x^3-3x+3

3. \mathrm{Solve\:}\:yy'\:=x^3-3x+3:\quad \frac{y^2}{2}=\frac{x^4}{4}-\frac{3x^2}{2}+3x+c_1

4. \mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}

5. \mathrm{Simplify}

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

7 0
3 years ago
Read 2 more answers
The 5's in 7,595_<br>How many times less?​
SpyIntel [72]

Answer:

it may be 79 or 7090 or

Step-by-step explanation

if u subtract 7595-55=7540

3 0
3 years ago
There are 1,295 students attending a small university.There are 714 women enrolled.What percent of the students are women?
BARSIC [14]
Total students = 1295

Number of women = 714

Percentage of women = 714/1295 x 100 = 55.14%

------------------------------------------------------------------
Answer: 55.14% of the students are women.
------------------------------------------------------------------
3 0
2 years ago
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