8.a)
A= (1,1) A’= (3,3)
B= (4,6) B’= (12,18)
C= (6,1). C= (18,3)
8b.)
A= (1,1) A’(0,5,0.5)
B= (4,6) B(2,3)
C= (6,1). C(3,0.5)
Hope this helped ! :)
Answer:
Distance = 10 km
Step-by-step explanation:
Let x be the number of hours taken from school to town and y be the number of hours taken back to the school
Then distance covered during first trip would be 10x (distance = speed*time) and during the second trip would be 8y. Both distances are equal.
=> 10x = 8y
Dividing both sides by 2
=> 5x = 4y
=> 5x-4y = 0 ------------------(1)
<u><em>The total time for both the trips is:</em></u>
=> x + y = 2.25 -------------------(2)
Multiplying eq (2) by 5
=> 5x+5y = 11.25 ---------------(3)
Subtacting (3) from (1)
=> 5x-4y-5x-5y = 0-11.25
=> -4y-5y = -11.25
=> -9y = -11.25
Dividing both sides by -9
=> y = 1.25 hrs
Putting in (2)
=> x + 1.25 = 2.25
=> x = 2.25 - 1.25
=> x = 1 hr
<u><em>Now, Calculating the Distance</em></u>
=> Distance = 10x
=> 10 ( 1 )
=> Distance = 10 km
-24+12d=2d-6+22
-24+12d=2d+16
-24+12d+24=2d+16+24
12d=2d+40
12d-2d=2d+40-2d
10d=40
10d/10=40/10
D=4
