Question

If a = 20 mm, b = 12 mm, and m∠C = 80°, what is the approximate area of ABC?

Answer 1

Answer:

118.18 mm^2

Step-by-step explanation:

Sides a and b form angle C, so the information given is a side-angle-side (SAS) problem.

Use the formula $A=\frac{1}{2}ab\sin{C}$.

$A=\frac{1}{2}(12)(20)\sin{80^\circ} \approx 118.18 \rm \,mm^2$