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Snowcat [4.5K]
3 years ago
14

If a = 20 mm, b = 12 mm, and m∠C = 80°, what is the approximate area of ABC?

Mathematics
1 answer:
Lana71 [14]3 years ago
8 0

Answer:

118.18 mm^2

Step-by-step explanation:

Sides <em>a</em> and <em>b</em> form angle C, so the information given is a side-angle-side (SAS) problem.

Use the formula A=\frac{1}{2}ab\sin{C}.

A=\frac{1}{2}(12)(20)\sin{80^\circ} \approx 118.18 \rm \,mm^2

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