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weqwewe [10]
3 years ago
10

Is -5^2 equal to (-5)^2 also ^ is equal to the phrase to the power of

Mathematics
2 answers:
guapka [62]3 years ago
7 0
<h3>Answer:</h3>

No.

Step-by-step explanation:

-5^2= -25,

while (-5)^2 = 25 because the "-" (negative) is inside of brackets.

^ is called Exponentiation.

ivann1987 [24]3 years ago
6 0

Answer: yes () just helps seperat the question in this case.

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Eloise started to solve a radical equation in this way: Square root of negative 2x plus 1 − 3 = x Square root of negative 2x plu
SOVA2 [1]
Eloise made these steps well:
 Square root of negative 2x plus 1 - 3 = x
 Square root of negative 2x plus 1 - 3 + 3 = x + 3
 The error comes in the next step:
 Square root of negative 2x plus 1 = x + 3
 Square root of negative 2x plus 1 -1 = x + 3 - 1
 Square root of negative 2x  = x + 2
 the number one is inside the root, therefore they can not be subtracted.
 answer
 error in the step:
  Square root of negative 2x  = x + 2

5 0
3 years ago
Read 2 more answers
What is the measure of m? 6 3 n 18 m = [?] Give your answer in simplest form. Enter​
alina1380 [7]

By solving a system of equations, we will see that m measures 12 units.

<h3>How to get the measure of m?</h3>

Notice that we have 3 right triangles.

Then we can write the equations:

cos(a) = 6/m

For the small triangle on the left, where m is the hypotenuse.

cos(a) = m/(6 + 18)

For the larger triangle (the one composed of the two triangles).

Where in both equations, angle "a" is the one in the top left.

Then we have the system of equations:

cos(a) = 6/m

cos(a) = m/(6 + 18)

Then we can write:

6/m = m/(6 + 18)

If we simplify the expression, we get:

6*(6 + 18) = m^2

6*(24) = m^2

144 = m^2

√144 = m = 12

Then we conclude that m measures 12 units.

If you want to learn more about right triangles:

brainly.com/question/2217700

#SPJ1

8 0
2 years ago
Solve for r. 35r-21&lt;-35r+19
Mnenie [13.5K]

Good morning ☕️

Answer:

r < \frac{4}{7}

Step-by-step explanation:

35r-21 < -35r+19

⇌ 35r + 35r < 19 + 21

⇌ 70r < 40

⇌ r < 40/70

⇌ r < 4/7

_________________________

:)

5 0
4 years ago
On a coordinate plane, point A is at (3, 3) and point B is at (negative 3, 3). Point B is the image of point A when A is rotated
Vladimir [108]

Answer:

Point B must be at the same distance from the the origin as point A.

Step-by-step explanation:

Coordinates of point A = (3, 3)

When point A is rotated 90° counterclockwise around the origin, coordinates of the new point B will be (-3, 3)

Distance from origin to point A = \sqrt{(3)^{2}+(3)^2}=3\sqrt{2}

Similarly, distance of point B from the origin = \sqrt{(3)^{2}+(3)^2}=3\sqrt{2}

Therefore, distances of both the points from the origin are same.

Point B must be at the same distance from the the origin as point A.

7 0
3 years ago
Can someone explain this
horsena [70]

9514 1404 393

Answer:

  • resultant force: 93.946∠-10.62° N
  • line of action: 17.314x +92.337y = 809.433

Step-by-step explanation:

We can use the notation a∠b to represent the (x, y) components (a·cos(b), a·sin(b)), where angle b is measured CCW from the +x direction. If we label the forces a, b, c, d clockwise from A, then we have ...

  a = 80∠0° = (80, 0)

  b = 60∠90° = (0, 60)

  c = 90∠45° = (63.640, 63.640)

  d = 150∠-110° = (-51.303, -140.954)

__

If we label point A the origin, then the clockwise torque on point A is the sum of products of the force x-component and its y location, and its y-component and the negative of its x location.

  T = (0, 0)·(80, 0) +(3, 0)·(0, 60) +(3, -8)·(63.640, 63.640) +(0, -8)·(-51.303, -140.954)

  T = 809.433 . . . . n·m, the CW torque on point A

__

The sum of forces is ...

  F = a +b +c +d = (92.337, -17.314) = 93.946∠-10.62° . . . N

__

This force, applied to the point of application, must generate the same torque as the given forces. That is ...

  F·(y, -x) = 809.433

Then the equation of the line of action is ...

  17.314x +92.337y = 809.433 . . . . . x and y in meters measured from A

Any point (x, y) on this line will serve as a point of application of the force. Unfortunately, this line of action does not pass through the rectangular plate. The attachment shows the point (D) on the line of action that is closest to point A.

_____

<em>Additional comment</em>

The resultant force could be decomposed into two forces acting <em>on the rectangular plate</em>. One could be of much larger magnitude, operating at the corner opposite point A. This force would provide the necessary torque. Another would be acting on point A, providing no torque, but with components such that the resultant has the correct magnitude and direction.

6 0
3 years ago
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