Question

If the diameter of a penny is 19.05 millimeters and the width of each penny is 1.52 millimeters, what is the approximate volume of the roll of pennies? Use 3.14 for π and round your answer to the nearest tenth.

Answer 1

We know that
[volume of the roll of pennies]=pi*r²*h
r=19.05/2-----> 9.525 mm
h=1.52 mm
[volume of the roll of pennies]=pi*(9.525)²*1.52---> 433.02 mm³----> 433 mm³

the answer is
433 mm³

Answer 2

Answer:

Volume of cylindrical roll of penny = 433 mm³ ( nearest tenth).

Step-by-step explanation:

Given : diameter of a penny is 19.05 millimeters and the width of each penny is 1.52 millimeters.

To find : volume of the roll of pennies.

Solution : We have given that

Diameter of a penny =  19.05 millimeters.

Width of each penny = 1.52 millimeters.

Volume of cylindrical roll of penny = pi * r² * h

Where, r = radius , h =height

Radius = $\frac{Diameter}{2}$

Radius=   $\frac{19.05}{2}$.

Radius = 9.525 mm

Plugging the values of r , h and pi = 1.14.

Volume of cylindrical roll of penny = pi * r² * h

Volume of cylindrical roll of penny =3.14 * (9.525)² * 1.52

Volume of cylindrical roll of penny = 433.02 mm³

Volume of cylindrical roll of penny = 433 mm³ ( nearest tenth).

Therefore, Volume of cylindrical roll of penny = 433 mm³ ( nearest tenth).