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Ivanshal [37]
3 years ago
11

Three people who work full-time are to work together on a project, but their total time on the project is to be equivalent to th

at of only one person working full-time. If one of the people is budgeted for one-half of his time to the project and a second person for one-third of her time, what part of the third worker’s time should be budgeted to this projec
Mathematics
1 answer:
arlik [135]3 years ago
7 0
1/6 of their time has to be put in to the project.
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If you covert the number 673/20 to a decimal, what would it be
fiasKO [112]

Answer:

33.65

Step-by-step explanation:

3 0
2 years ago
Write an equation for an exponential growth function where the initial population is 74 and the population quadruples during eac
Liono4ka [1.6K]
If the population quadruples every period say hour, that means the "rate of growth" is 300%, so whatever the current amount, increased by 3 times as much is 4 times the current amount, or a quadrupled amount.

\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=I(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\to &74\\
r=rate\to 300\%\to \frac{300}{100}\to &3.00\\
t=\textit{elapsed time}\\
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6 0
3 years ago
I am a 3-digit number. If you switch my first and last digits, I decrease by 297. Also, my
malfutka [58]

Answer:

  • 865

Step-by-step explanation:

Let the 3-digit number is <u>abc</u> = 100a + 10b + c.

<u>We have:</u>

  • 100a + 10b + c - 100c - 10b - a = 297
  • b = a - 6
  • a = 2c - 2

<u>Simplify the first equation:</u>

  • 99a - 99c = 297
  • a - c = 3
  • a = c + 3

<u>Solve for c by substitution:</u>

  • 2c - 2 = c + 3
  • 2c - c = 3 + 2
  • c = 5

<u>Find a:</u>

  • a = 3 + 5 = 8

<u>Find b:</u>

  • b = 8 - 2 = 6

<u>The number is:</u>

  • 865
3 0
2 years ago
72
Zigmanuir [339]

Answer:

Ai. Arithmetic sequence

Aii. Tn = 5 + 7n

Bi. Geometric

Bii. Tn = 8 × 2ⁿ¯¹

Step-by-step explanation:

To successfully answer the questions given above, note the following:

1. If the sequence is Arithmetic, then:

2nd – 1st = 3rd – 2nd = common difference (d)

2. If the sequence is geometric, then,

2nd / 1st = 3rd / 2nd = common ratio (r)

3. A sequence can not be arithmetic geometric at the same time.

4. The nth term of arithmetic sequence is:

Tn = a + (n – 1)d

5. The nth term of geometric sequence is:

Tn = arⁿ¯¹

A. Sequence => 12, 19, 26

i. Determination of the type of sequence.

We'll begin by calculating the common difference

1st term = 12

2nd term = 19

3rd term = 26

Common difference (d) = 2nd – 1st

d = 19 – 12 = 7

OR

d = 3rd – 2nd

d = 26 – 19 = 7

Since a common difference exist in the sequence, the sequence is arithmetic sequence.

ii. Determination of the nth term.

Common difference (d) = 7

1st term (a) = 12

nth term (Tn) =?

Tn = a + (n – 1)d

Tn = 12 + (n – 1)7

Tn = 12 + 7n – 7

Tn = 5 + 7n

B. Sequence => 8, 16, 32

Bi. Determination of the type of sequence.

Let us begin by calculating the common ratio.

1st term = 8

2nd term = 16

3rd term = 32

Common ratio (r) = 2nd / 1st

r = 16 / 8

r = 2

OR

r = 3rd / 2nd

r = 32 / 16

r = 2

Since a common ratio exist in the sequence, the sequence is geometric.

Bii. Determination of the nth term.

Common ratio(r) = 2

1st term (a) = 8

nth term =?

Tn = arⁿ¯¹

Tn = 8 × 2ⁿ¯¹

8 0
2 years ago
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Verdich [7]
145 divided by 7 =20.71
a little sketch on my answer <span />
6 0
3 years ago
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