Four is greater than y, and -1 is less than y
Answer:
f(2)= -4 f(3)= 1
Step-by-step explanation:
Answer:
The probably genotype of individual #4 if 'Aa' and individual #6 is 'aa'.
Step-by-step explanation:
In a non sex-linked, dominant trait where both parents carry and show the trait and produce children that both have and don't have the trait, they would each have a genotype of 'Aa' which would produce a likelihood of 75% of children that carry the dominant traint and 25% that don't. Since the child of #1 and #2, #5, does not exhibit the trait, nor does the significant other (#6), then they both must have the 'aa' genotype. However, since #4 displays the dominant trait received from the parents, it is more likely they would have the 'Aa' genotype as by the punnet square of 'Aa' x 'Aa', 50% of their children would have the 'Aa' phenotype.
The answer would be true.
So lets do it like this:
z = (X-Mean)/SD
<span>z1 = (8-12)/2 = - 2 </span>
<span>z2 = (16-12)/2 = + 2 </span>
<span>According to the Empirical Rule 68-95-99.7 </span>
<span>Mean more or less 2SD covers 95% of the values </span>
So t<span>he percentage of data points falling between 8 and 16 = 95%
</span>I hope this can help
