Using your periodic table if you look at it 3-11 are tansition metals so the horizontal Group Number will help if the group number has to digits just remove the one so if it were to be 13, the valence would be 3, if it were 14 the valence would be ,4 if it were 15, the valence would be 5, if it were 16 the valence would be 6, if it were 17 the valence would be 7 if it were group 18 the valence would be 8 so if anymore help needed to explain hit me up
<span>Answer:
Therefore, x component: Tcos(24°) - f = 0 y component: N + Tsin(24°) - mg = 0 The two equations I get from this are: f = Tcos(24°) N = mg - Tsin(24°) In order for the crate to move, the friction force has to be greater than the normal force multiplied by the static coefficient, so... Tcos(24°) = 0.47 * (mg - Tsin(24°)) From all that I can get the equation I need for the tension, which, after some algebraic manipulation, yields: T = (mg * static coefficient) / (cos(24°) + sin(24°) * static coefficient) Then plugging in the values... T = 283.52.
Reference https://www.physicsforums.com/threads/difficulty-with-force-problems-involving-friction.111768/</span>
Answer:

Explanation:
Given data:
Momentum of moving model train, 
Mass of the stationary model train, 
Initial speed of the stationary model train, 
Assume there is no external force is acting on the given train system.
In this case, the total linear momentum of the trains would be conserved.
Let the final linear momentum of the trains be 
Thus,





The pressure value is given by the equation,

Where,
represents the density of the liquid
g= gravity
h= Heigth
A) For the measurement of the guage pressure we have the data data,



Replacing we get,

P_g = 12395Pa[/tex]
In order to find the Absolute pressure, we perform a sum between the atmospheric pressure and that of the Gauge,
B) The atmospheric pressure at sea level is 101325Pa, assuming ideal conditions, we will take this pressure for our calculation, so

Answer:
4776.98 N is the minimum force to start the rise.
Explanation:
We can use the first Newton's law to find the minimum force to move the block.
So we will have:

Where:
- F is the force
- W(x) is the weight of the block in the x direction, W = mg*sin(15)
- F(f) is the static friction force (F(f) = μN), μ is the static friction coefficient 0.4.





Therefore 4776.98 N is the minimum force to move the block.
I hope it helps you!