If the two forces on an object are equal in size and opposite in direction, the forces are balanced, and no change

Physics

1 answer:

murzikaleks [220]3 years ago

4 0

Answer:

a rope being pulled from both sides with equal force

Explanation:

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What is the power of a student that has done a work of 10 joules in 10 seconds

Alla [95]

Answer:

1 Watt

Explanation:

P=W/t

P=10/10

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4 years ago

A rope of negligible mass is wrapped around a 225-kg solid cylinder of radius 0.400 m. The cylinder is suspended several meters

vodomira [7]

Answer:

a)6.67 m/s2

b)16.7 rad/s2

c)increasing angular acceleration

Explanation:

a) It's because the system is not just mass of the man, it consists of the man holding a rope wrapped around a cylinder, not just a man free falling. So you would have to consider the rotating cylinder under the torque created by the man gravity force.

Let g = 10m/s2

T = mgd =75*10*0.4 = 300 N.m

The from the mass moments inertial of the solid cylinder:

$I = \frac{Mr^2}{2} = \frac{225*0.4^2}{2} = 18 kgm^2$

we can calculate the angular acceleration of the cylinder:

$\alpha = \frac{T}{I} = \frac{300}{18} = 16.7 rad/s^2$

then translate that to acceleration:

$a = \alpha * r = 16.7*0.4 = 6.67 m/s^2$

c) if the mass of the rope is not neglected, that means the force of gravity increases as the rope unwrapping around the cylinder, so the torque increases. Also the moment of inertial of the rope-cylinder system decreases due to rope unwrapping. In the end, the angular acceleration is no longer constant, but increasing.

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4 years ago

on takeoff, the propellers on a uav (unmanned aerial vehicle) increase their angular velocity from rest at a rate of ω = (25.0t)

Rudik [331]

Hi there!

a)
We can find the angular velocity at t = 2.0 s by plugging in this value into the equation.

$\omega (t) = 25.0t \\\\\omega (2) = 25.0(2) = \boxed{50.0 \frac{rad}{s}}$