A trampoline has a spring constant of 3430 N/m how far will the trampoline sink when a 70 kg person steps on it
2 answers:
Answer:
20 cm
Explanation:
Force = mass * acceleration F = ma (1)
Spring equation is given as Force = Spring constant*Distance (2)
combine 1 & 2
F = ma = Spring constant*Distance
70 * 9.81 = 3430 * d
d = 0.2 m or 20 cm
F = ma = -kx
a = 9.81 m/s²
k = 3430 N/m
m = 70 kg
x = - ma/ k = 0.2m
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