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2 years ago

8

Define couple and give 2 examples

2 answers:

zvonat [6]2 years ago

6 0

A couple consists of two parallel forces that are equal in magnitude, opposite in sense and do not share a line of action. ... For example, the forces that two hands apply to turn a steering wheel are often (or should be) a couple. Each hand grips the wheel at points on opposite sides of the shaft.

Elodia [21]2 years ago

3 0

Answer:

Two equal and opposite parallel forces not acting along the same line, form a couple. A couple is always needed to produce the rotation.

For example, turning a key in a lock and turning a steering wheel.

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Barry slides across an icy pond. The coefficient of kinetic friction between his

Soloha48 [4]

The force of friction acting on him is 122 N. The correct answer is option C

<h3>What is Friction ?</h3>

Friction is a force that opposes the motion of a static or a moving object.

Given that Barry slides across an icy pond. The coefficient of kinetic friction between his shoes and the ice is 0.15. If his mass is 83 kg

The given parameters are;

Mass m = 83 kg

Coefficient of kinetic friction μ = 0.15

Frictional force $F_{r}$ = ?

The normal reaction N on the body = mg

N = 83 x 9.8

N = 813.4 N

The Frictional force formula is $F_{r}$ = μN

$F_{r}$ = 0.15 x 813.4

$F_{r}$ = 122.01 N

Therefore, the force of friction acting on him is 122 N approximately.

Learn more about Friction here: brainly.com/question/24338873

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4 0

2 years ago

A particle undergoes a constant acceleration of 3.90 m/s2. After a certain amount of time, its velocity is 12.2 m/s. (Where appl

Law Incorporation [45]

Answer:

$s_{f} = 14.312 m$

Explanation:

Since the particle is experimenting a constant acceleration, the displacement can be found by using this formula:

$v_{f}^{2} = v_{o}^{2} + 2 \cdot a \cdot (s_{f} - s_{o})$

Since $s_{o} = 0 m$ , the equation is simplified to this form:

$v_{f}^{2} = v_{o}^{2} + 2 \cdot a \cdot s_{f}$

Then, the displacement is now isolated:

$s_{f} = \frac{v_{f}^{2}-v_{o}^{2}}{2 \cdot a}$

Terms are replaced herein:

$s_{f} = \frac{(12.2 \frac{m}{s})^{2}-(6.1 \frac{m}{s})^{2}}{2 \cdot (3.90 \frac{m}{s^{2}}) } \\s_{f} = 14.312 m$

8 0

3 years ago

A simulation shows whether changing various weather conditions increases

LenKa [72]

Answer:I don’t know

Explanation:

i don’t know

4 0

2 years ago

Potassium is a crucial element for the healthy operation of the human

Dovator [93]

The second one if it’s on edge

8 0

2 years ago

Calculate the internal axial load at a point D if length L=7 ft. The part is subjected to loads P1=632 lbs, P2=888 lbs (applied

liraira [26]

Answer:

- 256 lbs

Explanation:

The internal axial load at point D can be calculated as the change in the subjected loads. if the magnitude of the horizontal direction = zero

$EF_x = 0$ ; Then:

internal axial load at point D = Δ P

= -(P₂ - P₁)

= - ( 888 lbs - 632 lbs)

= - 256 lbs

5 0

3 years ago