Answer:
6.2
Explanation:
<h2>I AM SMOooOooOooORT</h2><h2 /><h2>no but really trust the process</h2><h2 />
I think sand is just glass and other stuff
moles NaOH = c · V = 0.2753 mmol/mL · 43.44 mL = 11.959032 mmol
moles H2SO4 = 11.959032 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 5.979516 mmol
Hence
[H2SO4]= n/V = 5.979516 mmol / 54.69 mL = 0.1093 M
The answer to this question is [H2SO4] = 0.1093 M
Answer:
3.5 mL
Explanation:
Let us represent lauric acid with the symbol LaCOOH and the anion as LaCOO-. The reaction between the anion and H2SO4 is;
LaCOO-(aq) + H2SO4(aq) -----> LaCOOH(aq) + HSO4-(aq)
Number of moles of LaCOO- = 2.75 g/200 g/mol = 0.014 moles
Since the mole ratio of the reaction is 1:1, then the amount of H2SO4 required is also 0.014 moles
Then;
n = CV
n = number of moles
C= concentration
V = volume
V = n/C
V = 0.014 moles/4.0 M
V= 3.5 * 10^-3 L
V = 3.5 mL
Because gases are less dense than a liquid and a solid
