Answer:
35.9°C
Explanation:
Given parameters:
Mass of water in bath = 8.1kg
Initial temperature of water = 33.9°C
Quantity of heat flow = 69kJ
Specific heat capacity of water = 4.18J*g*K
Unknown:
New temperature of water bath =?
Solution:
The quantity of heat in a body is given using the expression below;
H = m c ΔT
H is the amount of heat
m is the mass
c is the specific heat capacity
ΔT is the change in temperature
ΔT = T₂ - T₁
We are to solve for T₂;
4.18J.g.K is the specific heat and it is the same as 4180J/kgK
now solve for ΔT
69000 = 8.1 x 4180 x ΔT
ΔT = 2.04
T₂ = 2.04 + 33.9 = 35.9°C