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aalyn [17]
3 years ago
10

A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains of water at . During the react

ion of heat flows out of the bath and into the flask. Calculate the new temperature of the water bath. You can assume the specific heat capacity of water under these conditions is 4.18J.g.K. Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
Archy [21]3 years ago
5 0

Answer:

 35.9°C

Explanation:

Given parameters:

Mass of water in bath = 8.1kg

Initial temperature of water = 33.9°C

Quantity of heat flow = 69kJ

Specific heat capacity of water  = 4.18J*g*K

Unknown:

New temperature of water bath =?

Solution:

The quantity of heat in a body is given using the expression below;

             H  = m c ΔT

H is the amount of heat

m is the mass

c is the specific heat capacity

ΔT is the change in temperature

  ΔT  = T₂  - T₁

We are to solve for T₂;

4.18J.g.K is the specific heat and it is the same as 4180J/kgK

 now solve for ΔT

                   69000 = 8.1  x 4180 x ΔT

                   ΔT = 2.04

T₂   = 2.04 + 33.9  = 35.9°C

     

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Answer:

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Explanation:

Considering the ideal gas equation as:

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At same volume, for two situations, the above equation can be written as:-

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Given ,  

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The conversion of T( °C) to T(K) is shown below:

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So,  

T₁ = (21.7 + 273.15) K = 294.85 K  

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Using above equation as:

\frac{{n_1}\times {T_1}}{P_1}=\frac{{n_2}\times {T_2}}{P_2}

\frac{{1.50\ mol}\times {294.85\ K }}{3.75\ atm}=\frac{{n_2}\times {301.25\ K  }}{0.998\ atm}

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Solving for n₂ , we get:

n₂ = 0.39 mol

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