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aalyn [17]
3 years ago
10

A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains of water at . During the react

ion of heat flows out of the bath and into the flask. Calculate the new temperature of the water bath. You can assume the specific heat capacity of water under these conditions is 4.18J.g.K. Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
Archy [21]3 years ago
5 0

Answer:

 35.9°C

Explanation:

Given parameters:

Mass of water in bath = 8.1kg

Initial temperature of water = 33.9°C

Quantity of heat flow = 69kJ

Specific heat capacity of water  = 4.18J*g*K

Unknown:

New temperature of water bath =?

Solution:

The quantity of heat in a body is given using the expression below;

             H  = m c ΔT

H is the amount of heat

m is the mass

c is the specific heat capacity

ΔT is the change in temperature

  ΔT  = T₂  - T₁

We are to solve for T₂;

4.18J.g.K is the specific heat and it is the same as 4180J/kgK

 now solve for ΔT

                   69000 = 8.1  x 4180 x ΔT

                   ΔT = 2.04

T₂   = 2.04 + 33.9  = 35.9°C

     

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Carbon disulfide has an unusual property of being able to dissolve several nonmetals. What are the boiling points and freezing p
nydimaria [60]

<u>Answer:</u> The freezing and boiling points of the solution is -114.34°C and 48.95°C respectively

<u>Explanation:</u>

  • <u>Calculating the freezing point:</u>

Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.

The equation used to calculate depression in freezing point follows:

\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Freezing point of pure solution = -110.8°C

i = Vant hoff factor = 1 (For non-electrolytes)

K_f = molal freezing point constant = 3.83°C/m

m_{solute} = Given mass of solute (P_4) = 8.44 g

M_{solute} = Molar mass of solute (P_4) = 124 g/mol

W_{solvent} = Mass of solvent (carbon disulfide) = 60.0 g

Putting values in above equation, we get:

-110.8-\text{Freezing point of solution}=1\times 3.83^oC/m\times \frac{8.44\times 1000}{124g/mol\times 60.0}\\\\\text{Freezing point of solution}=-114.34^oC

Hence, the freezing point of solution is -114.34°C

  • <u>Calculating the boiling point:</u>

Elevation in boiling point is defined as the difference in the boiling point of solution and freezing point of pure solution.

The equation used to calculate elevation in boiling point follows:

\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=iK_bm

Or,

\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Boiling point of pure solution = 46.3°C

i = Vant hoff factor = 1 (For non-electrolytes)

K_b = molal boiling point constant = 2.34°C/m

m_{solute} = Given mass of solute (P_4) = 8.44 g

M_{solute} = Molar mass of solute (P_4) = 124 g/mol

W_{solvent} = Mass of solvent (carbon disulfide) = 60.0 g

Putting values in above equation, we get:

\text{Boiling point of solution}-46.3=1\times 2.34^oC/m\times \frac{8.44\times 1000}{124g/mol\times 60.0}\\\\\text{Boiling point of solution}=48.95^oC

Hence, the boiling point of solution is 48.95°C

7 0
3 years ago
Convert 840 mL to liters ( be sure to keep the appropriate number of significant figures - also, only enter a number DO NOT INCL
Sholpan [36]
0.84. I think ... sorry if this is wrong!
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3 years ago
If 200cm of gas at S.T.P. has a mass of 0.268g.
STALIN [3.7K]

Answer:

Debate Topics For Teens

by Loraine Walters

Created: 17.10.2019

Updated: 27.12.2019

Debate Topics For Teens

For teenagers, debating is not only a fun activity but also a quite useful one. In the process, teenagers are able to improve their public speaking, research, and critical thinking skills. By being involved in a debate event organized by a school, teenagers are given a chance to express their opinion regarding a controversial topic or current events as well as to develop good and valid arguments for and against a certain subject.

If you want to promote critical reasoning and analysis among teenagers, be sure to go over these debate topics for teens and choose the ones that you think will suit their interests best. An interesting topic can help students to learn how to express their point of view and understand that it is valued. All in all, teens are about to enter the adult world, critical thinking and research will help them on their journey, and each school has the resources necessary for their development.

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Year round education is not a good idea for student learning.

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