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emmainna [20.7K]
3 years ago
5

How does the volume of a gas compare to the space between the particles of a gas is at normal pressure?

Chemistry
1 answer:
xenn [34]3 years ago
6 0
As the volume of a gas increases, so does the space between the particles at STP.
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The molar mass of vitamin A (C20H30O).
vivado [14]
Molar mass of C:  12.011 g/mol
The equation says C20, which means there are 20 carbon atoms in each molecule of Vitamin A.  So, we multiply 12.011 by 20 to get 240.22 g/mol carbon.

Molar mass of H:  1.0079 g/mol
The equation says C30, which means there are 30 hydrogen atoms in each molecule of Vitamin A. So, we multiply 1.0079 by 30 to get 30.237 g/mol hydrogen.

Molar mass of O: 15.999 g/mol
The equation says O without a number, which means there is only one oxygen atom in each molecule of Vitamin A.  So, we leave O at 15.999 g/mol.

Then, just add it up:
240.22 g/mol C + 30.237 g/mol H + 15.999 g/mol O = 286.456 g/mol C20H30O

So, the molar mass of Vitamin A, C20H30O, is approximately 286.5 g/mol.
4 0
3 years ago
A 0.0100 M solution of AgNO3 has a concentration of Ag ion equivalent to
qaws [65]

Answer:

0.0100M of AgNO3 contains 0.0100M of Ag+

Explanation:

AgNO3 when ionized yields Ag+ and NO3-. This means that the amount of AgNO3 in solution is equivalent to the amount of Ag+ and NO3- in that same solution.

1M of AgNO3 solution produces 1M of Ag+  

1M of AgNO3 solution produces 1M of NO3-

This occurs because of the complete ionization of AgNO3 in solution, allowing complete dissolution of the compound.

6 0
3 years ago
To begin, follow these steps:
s344n2d4d5 [400]

Answer: 6.2  grams of the sodium acetate can dissolve in 5 milliliters of water. if 124 grams of the sodium acetate dissolves in 100 milliliters of water, then 6.2 grams of the sodium acetate can dissolve in 5 milliliters of water.

4 0
3 years ago
Read 2 more answers
If 8.74 g of CuNO3 is dissolved in water to make a 0.700 M solution, what is the volume of the solution
Bess [88]
Hope this helps you.

4 0
3 years ago
The ka of phosphoric acid, h3po4, is 7.6  10–3 at 25 °c. for the reaction h3po4(aq) h2po4 – (aq) + h+ (aq) ∆h° = –14.2 kj/mol.
blsea [12.9K]
<span>Use the van't Hoff equation: ln ( K2 K1 ) = Δ Hº R ( 1 T1 ⒠1 T2 ) ln ( K2 7.6*10^-3 ) = -14,200 J 8.314 ( 1 298 ⒠1 333 ) ln ( K2 7.6*10^-3 ) = ⒠1708 ( 0.00035 ) ln ( K2 0.0076 ) = ⒠0.598 Apply log rule a = log b b a -0.598 = ln ( e ⒠0.598 ) = ln ( 1 e 0.598 ) Multiply both sides with e^0.598 K 2 e 0.598 = 0.0076 K e 0.598 e 0.598 = 0.0076 e 0.598 K 2 = 0.0076 e 0.598 = 4.2 ⋅ 10 ⒠3 K2 = 4.2 ⋅ 10 ⒠3</span>
7 0
3 years ago
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