How many trees are in the field

iren2701 [21]

Total Area = 2( 32 x 79) + (26 x 42) = 6148 m²

Number of 4 m² = 6148 ÷ 4 = 1537

Answer: The zoo can have 1537 plants.

8 0

3 years ago

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The pair of triangles that are congruent by the ASA criterion is . The pair of triangles that are congruent by the SAS criterion

anzhelika [568]

Answer:

The pair of triangles that are congruent by the ASA criterion isΔ ABC and Δ XYZ.

The pair of triangles that are congruent by the SAS criterion is Δ BAC and ΔRQP.

Step-by-step explanation:

Two triangles are congruent by ASA property if any two angles and their included side are equal in both triangles .In triangles Δ ABC and Δ XYZ the equal side 5 is between the two equal angles. So these triangles are congruent by ASA criterion.

Two triangles are congruent by SAS if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle .In triangles Δ BAC and ΔRQP. the included angles A and Q are equal and hence the triangles are congruent by SAS criterion.

5 0

3 years ago

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Could someone please solve this and explain how to do it?

galben [10]

Answer:

no clue buddy sry

Step-by-step explanation:

4 0

3 years ago

A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a

zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

$\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}$

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

$\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}$

Hence the answer is 0.1157

(ii) None is defective becomes