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3 years ago

Please help me with my math thank you

Mathematics

1 answer:

V125BC [204]3 years ago

6 0

Answer:

-3

Step-by-step explanation:

ur welcome :)))))

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the dilation from LMN to triangle L’M’N’ has a scale factor of 1/3 , write the coordinates for L’M’N’ and then graph both the pr

mina [271]

Answer:

Hi... U should do like this..

8 0

3 years ago

Write the number with the least value using the digits 1 through 9.use each digit only once.

amm1812

It would be 123,456,789 (if not counting decimals)

decimals would be like 0.123456789

8 0

3 years ago

Read 2 more answers

This one is a doozy for me, need help please

Maksim231197 [3]

Answer:

The correct answer is B

Step-by-step explanation:

Kinda complicated to explain, if you need me to then comment and I'll do it

4 0

2 years ago

Read 2 more answers

Express number 9 as a unit rate, you can also round

Katena32 [7]

125/200= 0.625 cents

0.625 cents to the nearest cent= 0.63

The unit rate is 0.63 miles.

Hope this helps!

6 0

3 years ago

(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the prop

zalisa [80]

Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

$\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})$

Compute the sample sizes as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}$

$n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}$

$=\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787$

Thus, the sample sizes are 6787.

(b)

Now it is provided that:

$\hat p_{1}=0.45\\\hat p_{2}=0.58$

Compute the sample size as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}$

$n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}$

$=\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666$

Thus, the sample sizes are 6666.

7 0

2 years ago