Answer:
(-∞, ∞)
Step-by-step explanation:
The domain of a function is the set of all possible input values (x-values).
An asymptote is a line that the curve gets infinitely close to, but never touches.
The arrows on either end of a graphed curve show that the function <u>continues indefinitely</u>. Therefore, we cannot assume there is an asymptote at x = -3 as we cannot see what happens to the curve as x approaches -∞.
Therefore, the domain of the given function is unrestricted:
- Solution: { x | -∞ < x < ∞ }
- Interval notation: (-∞, ∞)
Answer:
Step-by-step explanation:
If we choose chairs having odd number in the row
no of chairs from which selection is made = 10
no of chairs to be selected = 5
no of ways = 10C₅
similarly if we choose hairs having even numbers only ,
similar to above , no of ways
= 10C₅
Total no of ways
= 2 x 10C₅
= 2 x 10 x 9 x 8 x 7 x 6 / 5 x 4x3 x 2 x 1
= 504 .
Answer:
2x + 5y + 28 = 0
Step-by-step explanation:
since they are perpendicular,
m1 ×m2 = -1
5/2 × m2 = -1
m2 = -2/5
now,
y -y1 = M (x-x1)
y - (-4) = -2/5 ( x - (-4) )
y +4 = -2/5 ( x + 4 )
5 ( y +4 ) = -2 ( x+4)
5y +20 = -2x - 8
2x + 5y +20 + 8 =0
2x + 5y + 28 = 0
The first term of the arithmetic progression exists at 10 and the common difference is 2.
<h3>
How to estimate the common difference of an arithmetic progression?</h3>
let the nth term be named x, and the value of the term y, then there exists a function y = ax + b this formula exists also utilized for straight lines.
We just require a and b. we already got two data points. we can just plug the known x/y pairs into the formula
The 9th and the 12th term of an arithmetic progression exist at 50 and 65 respectively.
9th term = 50
a + 8d = 50 ...............(1)
12th term = 65
a + 11d = 65 ...............(2)
subtract them, (2) - (1), we get
3d = 15
d = 5
If a + 8d = 50 then substitute the value of d = 5, we get
a + 8 
5 = 50
a + 40 = 50
a = 50 - 40
a = 10.
Therefore, the first term is 10 and the common difference is 2.
To learn more about common differences refer to:
brainly.com/question/1486233
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