All categories

3 years ago

Please please help me

Mathematics

1 answer:

kondaur [170]3 years ago

6 0

Answer:

31%

Step-by-step explanation:

Of the 6101 students on financial aid, 1879 are graduates. This fraction is ...

1879/6101 × 100% ≈ 30.798% ≈ 31%

You might be interested in

Which method will NOT get you to the point (5,2.5)?

Vinvika [58]

Answer: 1st Choice Starting at the origin go 5 spaces to the right and then 2.5

8 0

3 years ago

Read 2 more answers

Describe features that determine a translation, rotation, and reflection.

yulyashka [42]

Hii I hope this helps! :)
Translation: It’s a transformation that moves every point in a figure the same distance in the same direction.
Rotation: It’s a a transformation that turns a figure about a fixed point.
Reflection: It’s a transformation that takes a shape/preimage and flips it across a line called the line of reflection to create a new shape/image.

7 0

3 years ago

Read 2 more answers

How many different ways can six people be arranged in a line?

lesantik [10]

There are six people which means that each person can be arranged in 6 various arrangements

6×6=36

Answer: There can be 36 different ways for 6 people to be arranged

8 0

4 years ago

The Pew Research Center reported that 73% of Americans who own a cell phone also use text messaging. In a recent local survey, 1

AnnZ [28]

Answer:

$z=\frac{0.775 -0.73}{\sqrt{\frac{0.73(1-0.73)}{200}}}=1.433$

Now we can find the p value. Since we have a bilateral test the p value would be:

$p_v =2*P(z>1.433)=0.152$

Since the p value is higher than the significance level of 0.1 we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

Do Not reject H0

Step-by-step explanation:

Information provided

n=200 represent the sample size slected

X=155 represent the cell phone owners used text messaging

$\hat p=\frac{155}{200}=0.775$ estimated proportion of cell phone owners used text messaging

$p_o=0.73$ is the value to verify

$\alpha=0.1$ represent the significance level

We need to conduct a z test for a proportion

z would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to verify if the true proportion of cell phone owners used text messaging is different from 0.73 so then the system of hypothesis are:

Null hypothesis: $p=0.73$

Alternative hypothesis: $p \neq 0.73$

The statistic to check this hypothesis is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the data given we got:

$z=\frac{0.775 -0.73}{\sqrt{\frac{0.73(1-0.73)}{200}}}=1.433$

Now we can find the p value. Since we have a bilateral test the p value would be:

$p_v =2*P(z>1.433)=0.152$

Since the p value is higher than the significance level of 0.1 we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

Do Not reject H0

6 0

3 years ago

Can y’all please help me ?

hjlf

Answer:

4.3

Step-by-step explanation:

6 0

3 years ago