Answer:
ethylene glycol (molar mass = 62.07 g/mol).
Explanation:
- We can solve this problem using the relation:
<em>ΔTf = Kf.m,</em>
ΔTf is the depression in the freezing point of tert-Butyl alcohol (ΔTf = freezing point of pure solvent - freezing point in presence of unknown liquid = 25.5°C - 15.3°C = 10.2°C).
Kf is the molal freezing point constant of tert-Butyl alcohol (Kf = 9.1 °C/m).
m is the molality of unknown liquid.
∵ ΔTf = Kf.m
<em>∴ m = ΔTf/Kf </em>= (10.2°C)/(9.1 °C/m) = <em>1.121 m.</em>
- We need to calculate the molar mass of the unknown liquid:
Molality (m) is the no. of moles of solute in 1.0 kg of solvent.
∴ m = (mass/molar mass) of unknown liquid/(mass of tert-Butyl alcohol (kg))
m = 1.121 m, mass of unknown liquid = 0.807 g, mass of tert-Butyl alcohol = 11.6 g = 0.0116 kg.
<em>∴ molar mass of unknown liquid = (mass of unknown liquid)/(m)(mass of tert-Butyl alcohol (kg)) </em>= (0.807 g)/(1.121 m)(0.0116 kg) = <em>62.06 g/mol.</em>
<em></em>
- So, the unknown liquid is:
<em>ethylene glycol (molar mass = 62.07 g/mol).</em>
Answer:
Its B I just took the test and got a 100%
Explanation:
Answer:
c. AgNO₃(aq) + NH₄Cl(aq) ->AgCl(s) + NH₄NO₃(aq)
Explanation:
We have to follow the <u>solubility rules</u> to check the states of each compound.
-) All the cholride salts are soluble EXCEPT those also containing: lead, silver or mercury.
-) All the nitrate and ammonium salts are soluble.
With this in mind , and would be soluble, so we have to use the <u>aqueosus state (aq).</u>
The then would have a <u>solid state (s)</u>.
The flow of electricity is an electric current. A path that an electric current follows is a circuit. A battery supplies energy to move electricity through a circuit.