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sveta [45]
3 years ago
13

When swimming the 5000 meter freestyle race, a swimmer travels at a steady pace of 68 seconds for each lap. Each lap of the pool

is 100 meters. How long will it take for this swimmer to swim the 5000 meters
Chemistry
1 answer:
Nina [5.8K]3 years ago
5 0

Well, since the race is a total of 5000m, and each lap is 100m, you would have to divide these two numbers to see how many laps around the pool it would be:

5000/100 = 50

Since his steady pace for a single lap is 68 seconds, you would multiple the number of laps, by the amount of time it would take him:

68*50 = 3,400 seconds

So in total it would take him 3,400 seconds, or 56 minutes 40 seconds.

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Actually, the electronegativity difference between carbon and hydrogen is just about 0.4. This meager difference in electronegativity corresponds to a nonpolar bond between the two atoms.

However, the electronegativity difference between nitrogen and hydrogen is about 0.9. This larger electronegativity difference corresponds to the existence of a polar covalent bond between the two atoms.

Hence the N-H bond is significantly polar unlike the C-H bond. This implies that CH4 molecules are only held together by weak dispersion forces while NH3 molecules are held together by stronger dipole-dipole interactions and hydrogen bonds.

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What is the basic difference between exergonic and endergonic reactions? Group of answer choices Exergonic reactions release ene
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The ___ of a bottle tells you how much liquid it can hold. what is the anewer
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In a single displacement reaction between sodium phosphate and barium, how much of each product (in grams) will be formed from 1
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Answer:

A. 3.36g of Na.

B. 14.62g of Ba3(PO4)2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

3Ba + 2Na3PO4 → 6Na + Ba3(PO4)2

Next, we shall determine the mass of Ba that reacted and the mass of Na and Ba3(PO4)2 produced from the equation.

This is illustrated below:

Molar Mass of Ba = 137g/mol

Mass of Ba from the balanced equation = 3 x 137 = 411g

Molar mass of Na = 23g/mol

Mass of Na from the balanced equation = 6 x 23 = 138g

Molar mass of Ba3(PO4)2 = (3 x 137) + 2[31 + (4x16)] = 411 + 2[31 + 64] = 601g/mol

Mass of Ba3(PO4)2 from the balanced equation = 1 x 601 = 601g

Summary:

From the balanced equation above,

411g of Ba reacted to produce 138g of Na and 601g of Ba3(PO4)2.

A. Determination of the mass of Na produced by reacting 10g of Ba.

From the balanced equation above,

411g of Ba reacted to produce 138g of Na.

Therefore, 10g of Ba will react to produce = (10 x 138)/411 = 3.36g of Na.

Therefore, 3.36g of Na is produced.

B. Determination of the mass of Ba3(PO4)2 produced by reacting 10g of Ba.

From the balanced equation above,

411g of Ba reacted to produce 601g of Ba3(PO4)2.

Therefore, 10g of Ba will react to produce = (10 x 601)/411 = 14.62g of Ba3(PO4)2.

Therefore, 14.62g of Ba3(PO4)2 is produced.

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