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givi [52]
2 years ago
10

8. What is the chemical formula for sulfuric acid? Explain in great detail.

Chemistry
2 answers:
-Dominant- [34]2 years ago
6 0

The chemical formula for sulfuric acid is H2SO4.

Detailed explanation:

This means that there are 2 atoms of hydrogen, 1 atom of sulfur, and 4 atoms of oxygen in a single molecule. Hope this helps!

stepladder [879]2 years ago
3 0

The answer is H2SO4.

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HELP HELP ME PLSS
Akimi4 [234]

Answer:

the average answer in maybe 60

6 0
3 years ago
Calculate the concentration expressed in percent, if 10 g of NaOH is diluted to 500 ml with water.
Zepler [3.9K]

If 10 g of NaOH is diluted to 500 ml with water then  the concentration expressed in percent is 0.5 mol/L .

Calculation ,

Given mass in gram = 10 g

Number of moles = given mass /molar mass = 10 g / 40 g/mol = 0.25mole

Given volume in ml = 500 ml

Given volume in liter  = 0.5 L

Putting the value of mass and volume in equation i we get concentration expressed in percent .

C = number of moles ×100/ volume in liter = 0.25mole ×100/ 0.5 L

C  =  0.5 mol/L

Concentration of solution in terms of percentage can be expressed in two ways

1) percentage by mass

2) percentage by volume

Hence, for liquid solutions, concentration is expressed in terms of percentage by volume.  

To learn more about concentration please click here ,

brainly.com/question/10380236

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5 0
1 year ago
Given pH = 3.50 Find: [H3O+] and [OH-] Is this acidic, basic or neutral?
lys-0071 [83]

Answer:

Explanation:

Given parameters:

           pH = 3.50

Unknown:

    concentration of [H₃0⁺] = ?

    concentration of [OH⁻] = ?

Solution:

In order to find the unknown, we use some simple expressions which best explains the pH scale and the equilibrium systems of aqueous solutions.

         pH = -log₁₀[H₃O⁺]

         [H₃O⁺] = inverse log₁₀ (-pH) = 10^{-pH} = 10^{-3.5}

          [H₃O⁺] = 3.2 x 10⁻⁴moldm⁻³

       

For the  [OH⁻]:

       we use : pOH = -log₁₀ [OH⁻]

     Recall: pOH + pH = 14

                  pOH = 14 - pH = 14 - 3.5 = 10.5

  Now we plug the value of pOH into pOH = -log₁₀ [OH⁻]

                                   [OH⁻] = 10^{-pOH}

                        [OH⁻] = 10^{-10.5} = 3.2 x 10⁻¹¹moldm⁻³

The solution is acidic as the concentration of H₃0⁺ is more than that of the OH⁻ ions.

                   

8 0
3 years ago
some inkjet printers produce picoliter-sized drops. how many water molecules are there in one picoliter of water? the density of
GrogVix [38]

3.37 x 10¹⁰ molecules

Explanation:

Given parameters:

Volume of water = 1pL = 1 x 10⁻¹²L

Density of water = 1.00g/mL = 1000g/L

Unknown:

Number of water molecules = ?

Solution:

To solve this problem, we first find the mass of the water molecule in the inkjet.

       Mass of water = density of water x volume of water

Then, the number of molecules can be determined using the expression below:

        number of moles = \frac{mass of water}{molar mass of water}

 Number of molecules = number of moles x 6.02 x 10²³

Solving:

Mass of water = 1 x 10⁻¹² x 1000 = 1 x 10⁻⁹g

Number of moles:

Molar mass of H₂O = 2 + 16 = 18g/mol

Number of moles = \frac{1 x 10^{-12} }{18} = 5.6 x 10⁻¹⁴moles

Number of molecules =  5.6 x 10⁻¹⁴   x   6.02 x 10²³ = 33.7 x 10⁹

                                     = 3.37 x 10¹⁰ molecules

Learn more:

Number of molecules brainly.com/question/4597791

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4 0
3 years ago
Poor precision in scientific measurement may arise from
Arturiano [62]
<span>Based on the experience of the responder, to correctly calculate measurements in real-world. Firstly is to avoid errors as much as possible. Errors are what makes your measurement invalid and unreliable. There are two types of error which is called the systematic error and the random error. Each error has different sources. Words that were mentioned –invalid and unreliable are very important key aspects to determine that your measure is truly accurate and consistent. Some would recommend using the mean method, doing three trials in measuring and getting their mean, in response to this problem.</span>
7 0
4 years ago
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