All categories

3 years ago

What.is the orbital notation of magnesium

Chemistry

1 answer:

VMariaS [17]3 years ago

3 0

Answer:

The nex six electrons will go in the 2p orbital. The p orbital can hold up to six electrons. We'll put six in the 2p orbital and then put the remaining two electrons in the 3s. Therefore the Magnesium electron configuration will be 1s22s22p63s2.

Explanation:

You might be interested in

A student was assigned the task of determining the identity of an unknown liquid. The student weighed a clean, dry 250-mL Erlenm

LiRa [457]

Answer:

248.4 mL

Explanation:

Erlenmeyer = 78.649 g

Erlenmeyer + Water = 327.039 g

Water = (Erlenmeyer + Water) - Erlenmeyer

Water = 327.039 - 78.649

Water = 248.4 g

if the density of water is 1 g/mL, we can say that each mL of water weigh 1 g, so we have 248.4 mL of water in the Erlenmeyer Flask.

4 0

3 years ago

When 1 mole of CO(g) reacts with H2O(l) to form CO2(g) and H2(g) according to the following equation, 2.80 kJ of energy are abso

Inga [223]

Answer: Endothermic, 2.80 kJ

Explanation

Since this reaction absorbs heat, it is endothermic.

The energy absorbed per mole CO is 2.80 kJ and this reaction is already balanced. q= 2.80 kJ

Hope this helps:)

6 0

3 years ago

Ava threw a hamster at her sister the other day she used 12N of force to accelerate the hamster at 8m/s2.what was the mass of th

xenn [34]

We are given:

The force applied on the poor hamster (F) = 12 N

Acceleration of the poor Hamster (a) = 8 m/s²

Solving for the mass of the Poor Hamster:

From newton's second equation of motion, we know that:

F = ma

replacing the given values

12 = 8 * m

m = 12/8 kg

m = 3/2 kg

The poor Hamster weighs 3/2 kg

8 0

3 years ago

A patients blood is tested for growth hormone which has a molecular mass of 848.952g/mol. The test results show a normal concent

rusak2 [61]

Answer:

$\boxed{4.7\times 10^{-9}}$

Explanation:

Data:

MM = 848.952 g/mol

c = 4.0 x 10⁻⁶ g/L

V = 1 L

Calculations:

(a) Mass of growth hormone

$\text{Mass} = \text{1 L} \times \dfrac{4.0 \times 10^{-6} \text{ g}}{\text{1 L}} = 4.0 \times 10^{-6} \text{ g}$

(b) Moles of growth hormone

$\text{Moles} = 4.0 \times 10^{-6} \text{ g} \times \dfrac{\text{1 mol}}{\text{848.952 g}} = 4.7\times 10^{-9}\text{ mol}\\\\\text{There are $\boxed{\mathbf{4.7\times 10^{-9}}\textbf{ mol}}$ of growth hormone in 1 L of blood.}$

8 0

4 years ago

Draw the structures of two stereoisomeric alkenes that would give 3-hexanol as the only major product of hydroboration followed

soldi70 [24.7K]

Answer:

cis-3-hexene and trans-3-hexene

Explanation:

Hydroboration oxidation is a method of preparation of alcohol from alkene.

Hydroboration follows anti-Markovnikoff rule in which alcohol group attached to less substituted carbon. Stereochemistry of the product is always syn that is H and OH attached to the same side of the double bond.

cis-3-hexene and trans-3-hexene undergoes hydroboration to form 3-hexanol.

7 0

3 years ago