Answer:
31
Step-by-step explanation:
(24/3)+(7x2)-(15/5)+(6*2)
8+(7x2)-(15/5)+(6*2)
8+14-(15/5)+(6*2)
8+14-3+(6*2)
8+14-3+12
22-3+12
19+12
31
Sorry if I did my math wrong :)
I have taken that test (although I don't see you're statements)
I believe the statements to choose from are:
A.) The slope of the line is −10.
B.) The slope of the line is 3.
C.) One point on the line is (3, 6).
D.) One point on the line is (3,−6)
<u>The answers are:</u>
A.) The slope of the line is -10
D.) One point on the line is (3,-6)
<u>Explanation: </u>
The given equation of line is (1). The point slope form of a line is (2) Where m is the slope of line and (x₁,y₁) are points. On comparing (1) and (2) we get The slope of given line is -10 and the line passing through the points (3,-6).
Consider expression 
First, you can factor it:
Since x is integer number, then you can see that x-1 is previous integer number (x-1 is 1 unit smaller than x).
Therefore, x-1 and x are two consecutive integers. When you have two consecutive integers, one of them is always even and one is always odd. Multiplying even integer number by odd integer number you always get even integer number.
Thus, 
is always even.
Answer:
50
Step-by-step explanation:
^^^^^^^^^ (please give me brainliest)
Answer:
Vertices: (1,-1), (-11, -1); Foci: (-15, -1), (5, -1)
Step-by-step explanation:
Center at (-5,-1) because of the plus 5 added to the x and the plus 1 added to the y.
a(squared)=36 which means a=6 and a=distance from center to vertices so add and subtract 6 from the x coordinate since this is a horizontal hyperbola, which is (1,-1), (-11,-1). From there you dont need to find the focus since there is only one option for this;
Vertices: (1,-1), (-11, -1); Foci: (-15, -1), (5, -1)
