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lisov135 [29]
3 years ago
13

What is 2*2 answerbbbbbbbbbbbbbbb

Mathematics
2 answers:
Oksana_A [137]3 years ago
4 0

Answer:

2x2 = 4

step-by-step explanation:

2 two times makes 4

victus00 [196]3 years ago
3 0

ItS 22 ThAtS ThE AnSwEr

Step-by-step explanation:

its actually 4

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If 12 children represents 12.5% of the people attending a concert, how many people are attending the concert
NeTakaya

96 people are attending the concert.

Step-by-step explanation:

Given,

Number of children at concert = 12

This represents 12.5% of the people attending concert.

Let,

p be the total people attending concert.

12.5% of p = 12

\frac{12.5}{100}*p=12\\0.125p=12

Dividing both sides by 0.125

\frac{0.125p}{0.125}=\frac{12}{0.125}\\p=96

96 people are attending the concert.

Keywords: percentage, division

Learn more about division at:

  • brainly.com/question/317601
  • brainly.com/question/306772

#LearnwithBrainly

7 0
3 years ago
A company invests $10,000 in a mutual fund account that earns a fixed
olga55 [171]

Answer:

a(t)=10000+1.08t

Step-by-step explanation:

t

1

2

3

Alt)

10,800.00

11,664.00

12,597.12

5 0
3 years ago
Sophie has two new fish. She feeds one fish
Zielflug [23.3K]

Step-by-step explanation:

One fish eats = 4 pellets

Second fish eats = 5 pellets

No of days one fish stays with Sophie = 72 ÷ 4 = 18 days

No of days second fish stays with Sophie = 72 ÷ 5 = 14.4 days

4 0
3 years ago
Read 2 more answers
Determine if the described set is a subspace. Assume a, b, and c are real numbers. The subset of R3 consisting of vectors of the
AveGali [126]

Answer:

Not a subspace

Step-by-step explanation:

(4,0,0) and (0,4,0) are vectors in R3 with zero or one entries being nonzero, but their sum, (4,4,0) has two nonzero entries.

7 0
3 years ago
Suppose that f: R --> R is a continuous function such that f(x +y) = f(x)+ f(y) for all x, yER Prove that there exists KeR su
Pachacha [2.7K]
<h2>Answer with explanation:</h2>

It is given that:

f: R → R is a continuous function such that:

f(x+y)=f(x)+f(y)------(1)  ∀  x,y ∈ R

Now, let us assume f(1)=k

Also,

  • f(0)=0

(  Since,

f(0)=f(0+0)

i.e.

f(0)=f(0)+f(0)

By using property (1)

Also,

f(0)=2f(0)

i.e.

2f(0)-f(0)=0

i.e.

f(0)=0  )

Also,

  • f(2)=f(1+1)

i.e.

f(2)=f(1)+f(1)         ( By using property (1) )

i.e.

f(2)=2f(1)

i.e.

f(2)=2k

  • Similarly for any m ∈ N

f(m)=f(1+1+1+...+1)

i.e.

f(m)=f(1)+f(1)+f(1)+.......+f(1) (m times)

i.e.

f(m)=mf(1)

i.e.

f(m)=mk

Now,

f(1)=f(\dfrac{1}{n}+\dfrac{1}{n}+.......+\dfrac{1}{n})=f(\dfrac{1}{n})+f(\dfrac{1}{n})+....+f(\dfrac{1}{n})\\\\\\i.e.\\\\\\f(\dfrac{1}{n}+\dfrac{1}{n}+.......+\dfrac{1}{n})=nf(\dfrac{1}{n})=f(1)=k\\\\\\i.e.\\\\\\f(\dfrac{1}{n})=k\cdot \dfrac{1}{n}

Also,

  • when x∈ Q

i.e.  x=\dfrac{p}{q}

Then,

f(\dfrac{p}{q})=f(\dfrac{1}{q})+f(\dfrac{1}{q})+.....+f(\dfrac{1}{q})=pf(\dfrac{1}{q})\\\\i.e.\\\\f(\dfrac{p}{q})=p\dfrac{k}{q}\\\\i.e.\\\\f(\dfrac{p}{q})=k\dfrac{p}{q}\\\\i.e.\\\\f(x)=kx\ for\ all\ x\ belongs\ to\ Q

(

Now, as we know that:

Q is dense in R.

so Э x∈ Q' such that Э a seq belonging to Q such that:

\to x )

Now, we know that: Q'=R

This means that:

Э α ∈ R

such that Э sequence a_n such that:

a_n\ belongs\ to\ Q

and

a_n\to \alpha

f(a_n)=ka_n

( since a_n belongs to Q )

Let f is continuous at x=α

This means that:

f(a_n)\to f(\alpha)\\\\i.e.\\\\k\cdot a_n\to f(\alpha)\\\\Also\\\\k\cdot a_n\to k\alpha

This means that:

f(\alpha)=k\alpha

                       This means that:

                    f(x)=kx for every x∈ R

4 0
3 years ago
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