Answer:
Following are the code to this question:
def sublist(l):#defining a method list sublist that accepts a list
val=[]#defining an empty list
x=0#defining x variable that store value 0
while(x<len(l)):#defining loop that check x is lessthen list length
if(l[x]==5):#defining if block that checks list value equal to 5
break#using break keyword
val.append(l[x])#add value in val list
x+= 1#increment the value of x variable by 1
return val#return val
l=[3,4,7,8,5,3,2]#defining list l
print(sublist(l))#using print method to call sublist method
Output:
[3, 4, 7, 8]
Explanation:
- In the above python code, a method "sublist" is declared that accepts a list, inside the method an empty list "val" and an integer variable x is defined that stores "0" value.
- In the method, a while loop is declared that checks list length and define if block to checklist element value equal to "5". which the condition is true it will return before values.
- In the last step, a list "l" is declared that holds value and used the print method to call sublist to prints its return value.
