<u>Answer:</u> The vapor pressure of the liquid is 0.293 atm
<u>Explanation:</u>
To calculate the vapor pressure of the liquid, we use the Clausius-Clayperon equation, which is:
![\ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}[\frac{1}{T_1}-\frac{1}{T_2}]](https://tex.z-dn.net/?f=%5Cln%28%5Cfrac%7BP_2%7D%7BP_1%7D%29%3D%5Cfrac%7B%5CDelta%20H_%7Bvap%7D%7D%7BR%7D%5B%5Cfrac%7B1%7D%7BT_1%7D-%5Cfrac%7B1%7D%7BT_2%7D%5D)
where,
= initial pressure which is the pressure at normal boiling point = 1 atm
= pressure of the liquid = ?
= Heat of vaporization = 28.9 kJ/mol = 28900 J/mol (Conversion factor: 1 kJ = 1000 J)
R = Gas constant = 8.314 J/mol K
= initial temperature = 341.88 K
= final temperature = 305.03 K
Putting values in above equation, we get:
![\ln(\frac{P_2}{1})=\frac{28900J/mol}{8.314J/mol.K}[\frac{1}{341.88}-\frac{1}{305.03}]\\\\\ln P_2=-1.228atm\\\\P_2=e^{-1.228}=0.293atm](https://tex.z-dn.net/?f=%5Cln%28%5Cfrac%7BP_2%7D%7B1%7D%29%3D%5Cfrac%7B28900J%2Fmol%7D%7B8.314J%2Fmol.K%7D%5B%5Cfrac%7B1%7D%7B341.88%7D-%5Cfrac%7B1%7D%7B305.03%7D%5D%5C%5C%5C%5C%5Cln%20P_2%3D-1.228atm%5C%5C%5C%5CP_2%3De%5E%7B-1.228%7D%3D0.293atm)
Hence, the vapor pressure of the liquid is 0.293 atm
<h2>Let us solve for it </h2>
Explanation:
Energy
It is ability to do work .
There are so many forms of energy .
out of which mechanical energy is also one of the form .
Mechanical energy
It is the energy possessed by the body by virtue of its motion and state .
It is of two types :
- Kinetic energy
- Potential energy
Kinetic energy
It is the energy possessed by the body by virtue of its motion .
Its expression is :
K.E=1/2mv²
Here in above question it is given that :
mass = 2Kg
V=10m/sec
K.E will be = 1/2 x 2 x 10 x 10
K.E=100 J
I hope my calculation is correct :P
We have to discuss here whether mole should be considered as a base unit in SI system or not.
The answer is- mole is considered as base unit in SI system.
There are seven base units in the SI system. They are- kilogram (kg) for mass, second (s) for time, kelvin (K) for temperature, ampere (A) for electric current, mole (mol) for the amount of substance, candela (cd) for luminous intensity and meter (m) is for distance.
Mole is defined as the amount of substance that contains as many elementary entities as there are atoms in 0.012 kilogram of carbon-12. One mole contains exactly 6.022 X 10²³ elementary entities.
This number 6.022 X 10²³ is the fixed numerical value which is called Avogadro number which is universally accepted number. Hence mole is also base unit in the SI system.
