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4 years ago

When aluminum oxidizes in air it forms aluminum oxide (al2o3) if a 51 sheet?

1 answer:

8 0

Answer: mol Al2O3 x 1 mol Al/ 2 mol Al2O3= .25 mol Al The balanced equation tells us that it takes 4 moles of Al to produce 2 moles of Al2O3. 0.50 moles Al2O3 x (4 moles Al / 2 moles Al2O3) = 1.0 moles Al 1.0 moles Al x (27.0 g Al / 1 mole Al) = 27.0 g Al

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Lithium has two isotopes, lithium-6 weighing 6.015 amu (7.5% abundance), and lithium-7

Semenov [28]

Answer:

The answer is 6.941 but I dont really have the explanation

Explanation:

8 0

3 years ago

Chemistry vocabulary and answer

finlep [7]

Answer:

you forgot to attach a picture :)

Explanation:

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3 years ago

What precipitate, if any, forms when aqueous solutions of li2so4 and nai are mixed?

aleksandrvk [35]

Hello!

When aqueous solutions of Li₂SO₄ and NaI are mixed the following reaction occurs:

Li₂SO₄(aq) + 2NaI(aq) → 2LiI(aq) + Na₂SO₄(aq)

The compounds produced from this reaction are all soluble, so no precipitate is formed. We know that those compounds (LiI and Na₂SO₄) are soluble because of the solubility rules which states that salts from Group I elements (Li⁺, Na⁺) are soluble.

Have a nice day!

4 0

4 years ago

a television remote control operates at 319 THz, what is the wavelength of the infrared light in nanometers?

AURORKA [14]

Given:

Frequency (ν) = 319 THz

To determine:

The wavelength corresponding to the given frequency

Explanation:

Wavelength (λ) and Frequency(ν) are related as:

λ = c/ν

where c = speed of light = 3*10⁸ m/s

Now:

SI unit of frequency is Hertz (Hz) also expressed as cycles per second

i.e 1 Hz = 1 s⁻¹

1 Terahertz (THz) = 10¹² Hz

therefore the given frequency ν = 319 *10¹² s⁻¹

λ = 3 * 10⁸ ms⁻¹/319 *10¹² s⁻¹ = 940 * 10⁻⁹ m

since 1 nanometer (nm) = 10⁻⁹ m

The wavelength is λ = 940 nm

Ans: The infrared wavelength = 940 nm

7 0

4 years ago

At a certain temperature the rate of this reaction is second order in with a rate constant of Suppose a vessel contains at a con

grigory [225]

Answer: The given question is incomplete. The complete question is:

At a certain temperature the rate of this reaction is second order in $NH_4OH$ with a rate constant of $34.1M^{-1}s^{-1}$ . $NH_4OH(aq)\rightarrow NH_3(aq)+H_2O(aq)$

Suppose a vessel contains $NH_4OH$ at a concentration of 0.100 M Calculate how long it takes for the concentration of $NH_4OH$ to decrease to 0.0240 M. You may assume no other reaction is important. Round your answer to 2 significant digits.

Answer: It takes 0.93 seconds for the concentration $NH_4OH$ to decrease to 0.0240 M.

Explanation:

Integrated rate law for second order kinetics is given by:

$\frac{1}{a}=kt+\frac{1}{a_0}$