An: Calculate the molarity of a solution made by adding 120 g of NaOH (40.00 g/mol) to enough water to make 500.0 mL of solution. a) 4.0 M b) 6.0 M c) 1.0 ...
Explanation:
Answer:
pH = 8.34
Explanation:
The equilbriums of the amphoteric HCO₃⁻ (Ion of NaHCO₃) are:
H₂CO₃ ⇄ <em>HCO₃⁻</em> + H⁺ Ka1 <em>-Here, HCO₃⁻ is acting as a base-</em>
<em>HCO₃⁻</em>⇄ CO₃²⁻ + H⁺ Ka2 <em>-Here, is acting as an acid-</em>
Where Ka1 = 4.3x10⁻⁷ and Ka2 = 4.8x10⁻¹¹. As pKa = -log Ka:
pKa1 = 6.37; pKa2 = 10.32
As the pH of amphoteric salts is:
pH = (pKa1 + pKa2) / 2
<h2>pH = 8.34</h2>
Answer:
Sp3
Explanation:
Hydrocarbon can be defined as an organic compound that comprises of hydrogen and carbon only. Some examples of hydrocarbon are methane, butane, ethane, ethene, etc.
Hybridization can be defined as a phenomenon which involves the combination of two or more atomic orbitals to form the same number of hybrid orbitals, with each of the orbitals having the same shape and energy.
In Organic chemistry, ethane is considered to be a tetrahedral carbon and it's Sp3 hybridized.
A tetrahedral carbon typically comprises of four bonds that are 109. 5° apart while a linear carbon atom comprises of two (2) bonds that are 180° apart.
Hence, the molecule of ethane posses a Sp3 hybridization because it has four bonds arrange with a tetrahedral geometry.
Answer:
78.7
Explanation:
The number has 4 significant figures: 7,8 6 and 5.
To round off to 3 significant figures, the target digit is the third significant figure in the number.The determining digit is the fourth significant figure in the number; it is 5 hence the target digit will go up by 1 and any digits to the right of it will be rounded down to 0.
Answer:
Explanation:
stoichiometry is used in cooking because it helps you determine the amount or proportion of compounds you will need in a chemical reaction. Stoichiometry is present in daily life, even in the cooking recipes we make at home. The reactions depend on the compounds involved and how much of each compound is needed to determine the product that will result.
