Answer
Find out the m∠6 .
To prove
As given
a∥e , m∥n , and m∠2 = 112°.
As m∥n
a is the transversal (A line that cuts across two or more (usually parallel) lines is called transverasl.)
Thus
∠ 2 = ∠3 ( Corresponding angle property )
∠3 = 112°
Also
a∥e and m is transversal .
∠ 3 = ∠6 = 112 ° ( Corresponding angle property )
Therefore
∠6 = 112°
Try this solution:
1. m∠A=m∠L; m∠B=m∠M and m∠C=m∠N;
2. m∠B=m∠M=35° and m∠C=m∠N=95°;
3. m∠A=m∠L=180°-(m∠B+m∠C)=180-35-95=50°
answer: 50°
Exercise 1:
exponential decay:
The function is given by:
y = A (b) ^ ((1/3) * t)
Where,
A = 600
We look for b:
(480/600) * (100) = 80%
b = 0.8
Substituting:
y = 600 * (0.8) ^ ((1/3) * t)
We check for t = 6
y = 600 * (0.8) ^ ((1/3) * 6)
y = 384
Answer:
exponential decay:
y = 600 * (0.8) ^ ((1/3) * t)
Exercise 2:
linear:
The function is given by:
y = ax + b
Where,
a = -60 / 2 = -30
b = 400
Substituting we have:
y = -30 * x + 400
We check for x = 4
y = -30 * 4 + 400
y = 280
Answer:
linear:
y = -30 * x + 400
Exercise 3:
exponential growth:
The function is given by:
y = A (b) ^ ((1/3) * t)
Where,
A = 512
We look for b:
(768/512) * (100) = 150%
b = 1.5
Substituting:
y = 512 * (1.5) ^ ((1/2) * t)
We check for t = 4
y = 512 * (1.5) ^ ((1/2) * 4)
y = 1152
Answer:
exponential growth:
y = 512 * (1.5) ^ ((1/2) * t)
