The point G on AB such that the ratio of AG to GB is 3:2 is; G(4.2, 2)
How to partition a Line segment?
The formula to partition a line segment in the ratio a:b is;
(x, y) = [(bx1 + ax2)/(a + b)], [(by1 + ay2)/(a + b)]
We want to find point G on AB such that the ratio of AG to GB is 3:2.
From the graph, the coordinates of the points A and B are;
A(3, 5) and B(5, 0)
Thus, coordinates of point G that divides the line AB in the ratio of 3:2 is;
G(x, y) = [(2 * 3 + 3 * 5)/(2 + 3)], [(2 * 5 + 3 * 0)/(2 + 3)]
G(x, y) = (21/5, 10/5)
G(x, y) = (4.2, 2)
Read more about Line segment partition at; brainly.com/question/17374569
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Answer:
18 bags
with 90/18 = 5 apples
and 72/18 = 4 oranges
in each bag
Step-by-step explanation:
Answer:
x=1
Z=35.4965
assuming you want y to be the height, y=5.916
Step-by-step explanation:
x/height=height/35
35x=y^2
using Pythagorean theorem
y^2+x^2=6^2
y^2+35^2=z^2
substituting for y^2
35x+x^2=6^2
x^2+35x-36=0
(x+36)(x-1)=0
x=1
y^2+x^2=6^2
substitute
y^2+1=36
y^2=35
y=5.916
y^2+35^2=z^2
substitute
35+1225=z^2
z^2=1260
z=35.4965
Answer:
3/4
Step-by-step explanation:
use a calculator
you would divide both sides by 6 to get your answer. i hope this helps :)
