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grin007 [14]
3 years ago
10

Step by step, to find solution to -4(6n-4)+3n=

Mathematics
2 answers:
Dimas [21]3 years ago
7 0

Answer:

-21n + 16

Step-by-step explanation:

Start with distributive property

-24n + 16 + 3n

Combine like terms

-21n + 16

There is a part of the equation missing so I can't solve completely

FrozenT [24]3 years ago
6 0
Hope this helps!!! Lmk if you have questions

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You take out a $32,000 loan. The amount that you must pay for your loan will increase at a rate of 4.5
seraphim [82]

Answer:

you owe $49,695 in total and $17,695 in interest alone

5 0
3 years ago
There are two differences between the bank statement and the check register describe each of them
Viefleur [7K]

Step-by-step explanation:

Bank statement would contains the following things as mentioned below:

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5 0
4 years ago
4 divided by 1/3 is 12 becuase
Alex17521 [72]

Answer:

12

Step-by-step explanation:

When we divide fractions we multiply instead since it's the opposite of division and we do the reciprocal. Reciprocal means we flip the fraction from 1/3 to 3/1

So:

4÷1/3 would become 4×3/1

4×3/1 is the same as 4×3

So:

4×3=12

That's why the answer is 12.

8 0
2 years ago
Suppose the system below is consistent for all possible values of f and g. What can you say about the coefficients c and d? Just
morpeh [17]

Answer:

The answer is "d \neq 3c,f and g are arbitrary".

Step-by-step explanation:

The matrix of the device is increased  

\left[\begin{array}{ccc}1&3&f\\ c&d&g\\ \end{array}\right]

Reduce the echelon row matrix  

\left[\begin{array}{ccc}1&3&f\\ c&d&g\\ \end{array}\right] \\\\R_1 \leftrightarrow  R_2 \\\\\frac{R_2 -1}{C R_1 \to R_2}   \sim   \left[\begin{array}{ccc} c&d&g\\ 0 & \frac{3c-d}{c}& \frac{cf-g}{c}\\ \end{array}\right]

Therefore, if 3c\neq 0 is d \neq  3c, the device is valid.  Therefore d \neq are arbitrary 3c, g and f.

7 0
3 years ago
Vhat is the value of the expression below when a -5.b = 7, and c = 6?<br> 9b - 4a + 2c
Vinvika [58]
7393=73-273 is he expression shown below
8 0
3 years ago
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