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Fed [463]
4 years ago
6

What is the least common multiple of 14 and 42 ( PLEASE HELP EXTRA POINTS !! ) ​

Mathematics
1 answer:
zaharov [31]4 years ago
3 0

Answer:

Prime factors of 14(<u><em>2</em></u>,7)

Prime factors of 42(2,3,<em><u>7</u></em>)

List all the prime factors that appear in either number, then multiply

2*7=14 LCM

Step-by-step explanation:

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Please help ASAP!!
marta [7]

Answer:

D. NM=12; mK=70°

Step-by-step explanation:

KN≈KM so they have the same 55° and then

180°-55°-55°=70° and

6*2=12

3 0
3 years ago
416/8 long division
Ganezh [65]
The answer for that question is 52
3 0
4 years ago
Which two values of x are roots of the polynomial below?
Julli [10]

Answer:

B. and C.

Step-by-step explanation:

1. Set the polynomial equal to zero:

x² + 5x + 7 = 0

2. Plug the given values of a, b, and c into the quadratic formula:

x=\frac{-5+-\sqrt{5^{2}-4(1)(7) } }{2(1)}

3. Solve the square root:

x=\frac{-5+-\sqrt{25-4(1)(7)} }{2(1)}

x=\frac{-5+-\sqrt{25-28} }{2(1)}

x=\frac{-5+-\sqrt{-3} }{2(1)}

4. Simplify the rest:

x=\frac{-5+-\sqrt{-3} }{2}

5. Separate the solutions:

x=\frac{-5+\sqrt{-3} }{2}  , x=\frac{-5-\sqrt{-3} }{2}

Thus, options B and C are the answers.

hope this helps!

4 0
2 years ago
On a coordinate plane, what is the distance between the points at (1,9) and the point (4, 9)?
sammy [17]

If you draw out a coordinate plane you will see that they , on their Y access, are both nine witch means that they a horizontal line so all you have to do is subtract the x access witch is 3.

hope this helped


4 0
4 years ago
Find the area of the parallelogram with vertices:________.
marin [14]

Answer:

97.98

Step-by-step explanation:

The area of the parallelogram PQR is the magnitude of the cross product of any two adjacent sides. Using PQ and PS as the adjacent sides;

Area of the parallelogram = |PQ×PS|

PQ = Q-P and PS = S-P

Given P(0,0,0), Q(4,-5,3), R(4,-7,1), S(8,-12,4)

PQ = (4,-5,3) - (0,0,0)

PQ = (4,-5,3)

Also, PS = S-P

PS = (8,-12,4)-(0,0,0)

PS = (8,-12,4)

Taking the cross product of both vectors i.e PQ×PS

(4,5,-3)×(8,-12,4)

PQ×PS = (20-36)i - (16-(-24))j + (-48-40)k

PQ×PS = -16i - 40j -88k

|PQ×PS| = √(-16)²+(-40)²+(-88)²

|PQ×PS| = √256+1600+7744

|PQ×PS| = √9600

|PQ×PS| ≈ 97.98

Hence the area of the parallelogram is 97.98

3 0
3 years ago
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