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mamaluj [8]
3 years ago
12

when this 3 digit number is rounded to the beater hundred it rounds to 900 .the digit in the ones place is the fifth odd number

you count beginning with one. the digit is 22.what is that number
Mathematics
1 answer:
jeka57 [31]3 years ago
4 0
859. 
<span>Because it rounds to 900, it must be somewhere between 850-899. The fifth odd number you count beginning with 1 is 9 (1, 3, 5, 7, 9). That leaves 859, 869, 879, 889, and 899. Then use a calculator to add them up, and 859 is the only one that adds up to 22.</span>
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Find the distance between the points (-9,0) and (2,5)
andreev551 [17]

Answer:

sqrt(146)

Step-by-step explanation:

The distance between these two points can be the hypotenuse of our right triangle.

We can create a right triangle with two legs of length 11 and 5. To solve for the hypotenuse, we apply the pythagorean theorem

sqrt(5^2+11^2)=sqrt(146)

I attached a graph to help you visualize the triangle and how it works.

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Round to the Nearest Ten
lora16 [44]

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Step-by-step explanation:

62 to the nearest ten is 60.

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The perimeter of a triangle is 510 feet and the sides are in the ratio of 11:16:24. Find the area of the triangle
Nutka1998 [239]

If the sides are in the ratio of 11:16:24, it means that they are all multiples of a same number x, according to these factors.

So, the shorter side is 11x feet long, the middle one is 16x feet long, and the longest side is 24x feet long.

This means that the perimeter is

11x+16x+24x = 51x feet long. But we know that this is 510 feet, so we have

51x = 510 \implies x = \cfrac{510}{51} = 10.

So, the three sides are 110, 160 and 240 feet long.

To find the area of a triangle knowing its three sides, you can use Heron's formula, which states that, if s is half the perimeter of the triangle whose sides are a,b,c, the area A is given by

A = \sqrt{s(s-a)(s-b)(s-c)}

In our case, s = 255, a = 110, b = 160, c = 240 so the formula becomes

A = \sqrt{255(255-110)(255-160)(255-240)} = \sqrt{255(145)(95)(15)} = \sqrt{52689375} \approx 7258.74

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3 years ago
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gladu [14]

Answer:

7 students

Step-by-step explanation:

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2 years ago
A ball of radius 15 has a round hole of radius 5 drilled through its center. Find the volume of the resulting solid. Hint: The u
OverLord2011 [107]

Answer:

The volume of the ball with the drilled hole is:

\displaystyle\frac{8000\pi\sqrt{2}}{3}

Step-by-step explanation:

See attached a sketch of the region that is revolved about the y-axis to produce the upper half of the ball. Notice the function y is the equation of a circle centered at the origin with radius 15:

x^2+y^2=15^2\to y=\sqrt{225-x^2}

Then we set the integral for the volume by using shell method:

\displaystyle\int_5^{15}2\pi x\sqrt{225-x^2}dx

That can be solved by substitution:

u=225-x^2\to du=-2xdx

The limits of integration also change:

For x=5: u=225-5^2=200

For x=15: u=225-15^2=0

So the integral becomes:

\displaystyle -\int_{200}^{0}\pi \sqrt{u}du

If we flip the limits we also get rid of the minus in front, and writing the root as an exponent we get:

\displaystyle \int_{0}^{200}\pi u^{1/2}du

Then applying the basic rule we get:

\displaystyle\frac{2\pi}{3}u^{3/2}\Bigg|_0^{200}=\frac{2\pi(200\sqrt{200})}{3}=\frac{400\pi(10)\sqrt{2}}{3}=\frac{4000\pi\sqrt{2}}{3}

Since that is just half of the solid, we multiply by 2 to get the complete volume:

\displaystyle\frac{2\cdot4000\pi\sqrt{2}}{3}

=\displaystyle\frac{8000\pi\sqrt{2}}{3}

5 0
3 years ago
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