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Ann [662]
3 years ago
14

Joanne has a cylindrical, above ground pool. the depth (height) of the pool is 1/2 of its radius, and the volume is 1570 cubic f

eet. What is the area of its bottom floor? The diameter of the pool floor must also be at most 22 feet.
Mathematics
1 answer:
diamong [38]3 years ago
5 0

Answer:

314 ft²

Step-by-step explanation:

Data provided in the question:

Depth (height) of the pool = \frac{1}{2} of its radius

let the radius be 'r' ft

thus,

Depth (height) of the pool, h = \frac{r}{2} ft

Volume of the pool = 1570 ft³

also,

Volume of cylinder = πr²h

thus,

1570 ft³ = πr²h

or

1570 ft³ = \pi r^2(\frac{r}{2})

or

3140 = 3.14 × r³                     [ π = 3.14 ]

or

r³ = 1000 ft³

or

r = 10 ft

Thus,

Area of the bottom surface = πr²

= 3.14 × 10²

= 314 ft²

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7. Which of the following can be determined from the graph below?
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Answer:

The ordered pair (6,25) is a solution to both

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Step-by-step explanation:

Part 7)

<em>step 1</em>

Find the equation of the line with positive slope

take the points (0,15) and (9,30)

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The formula to calculate the slope between two points is equal to

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substitute the given values

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m=\frac{15}{9}

simplify

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Find the equation of the line in slope intercept form

y=mx+b

we have

m=\frac{5}{3}

b=15

substitute

y=\frac{5}{3}x+15

<em>step 2</em>

Find the equation of the line with negative slope

take the points (0,40) and (8,20)

<em>Find the slope</em>

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute the given values

m=\frac{20-40}{8-0}

m=-\frac{20}{8}

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Find the equation of the line in slope intercept form

y=mx+b

we have

m=-\frac{5}{2}

b=40

substitute

y=-\frac{5}{2}x+40

step 3

Find the solution of the system

we know that

The solution of the system of equations is the intersection point both graphs

The intersection point is (6,25) ----> see the graph

therefore

The ordered pair (6,25) is a solution to both y=-\frac{5}{2}x+40  and  

y=\frac{5}{3}x+15

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