32miles/hr
Explanation:
Given parameters:
Distance 1 = 60miles
Time 1 = 2hrs
Distance 2 = 68miles
Time 2 = 2hrs
Unknown:
Average speed of the car = ?
Solution:
Average speed is the total distance covered in a particular duration of time.
Average speed = 
Total time taken = time 1 + time 2 = 2hrs + 2hrs = 4hrs
Total distance = distance 1 + distance 2 = 60miles + 68miles = 128miles
Average speed = 
= 32miles/hr
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Answer:
<em>Asha traveled a distance of 50 m</em>
<em>The displacement is 20 m north.</em>
Explanation:
<u>Distance and Displacement
</u>
A moving object constantly travels for some distances at defined periods of time. The total moved distance is the sum of each individual distance the object traveled. It can be written as:
dtotal=d1+d2+d3+...+dn
This sum is obtained independently of the direction the object moves.
The displacement only takes into consideration the initial and final positions of the object while moving. The displacement, unlike distance, is a vectorial magnitude and can even have magnitude zero if the object starts and ends the movement at the same point.
Asha walks 15 m west, 20 m north, and 15 m east. The total distance is
dt=15 m + 20 m + 15 m = 50 m
Asha traveled a distance of 50 m
Note the final position is 20 m above the initial position since she goes 15 m west and 15 m east. Thus the displacement is 20 m north.
Metallic and non-metallic
Hope this helps!
Explanation:
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