Answer:
18 groups are in the modern periodic table
Answer:
final temperature is 364.32 K
mass of air is 0.5423 kg
Explanation:
given data
pressure p1 = 380 kPa
volume v1 = 0.120 m³
temperature = 20°C = 20 + 273 = 293 K
pressure p2 = 3450 kPa
volume v2 = 5% increase
to find out
final temperature and the mass
solution
we consider here ideal gas
so equation is
p1v1 / t1 = p2v2/t2
put here all value and find t2
and v2 is = 0.120 ( 1 + 0.05) = 0.126 m³
so
t2 = p2v2/ p1v1 × t1
t2 = (450 × 0.126) / (380 × 0.120) × 293
t2 = 364.32 K
so final temperature is 364.32 K
and
mass = p2v2 / Rt2
here R gas constant is 0.287 kJ/kg.K
so
mass = (450 × 0.126) / (0.287 × 364.32 )
mass = 0.5423
so mass of air is 0.5423 kg
Answer:
Explanation:
a ) Time period T = 2 s
Angular velocity ω = 2π / T
= 2π / 2 = 3.14 rad /s
Initial moment of inertia I₁ = 200 + mr²
= 200 + 25 x 2.5²
=356.25
Final moment of inertia
I₂ = 200 + 25 X 1.5 X 1.5
= 256.25
b ) We apply law of conservation of momentum
I₁ X ω₁ = I₂ X ω₂
ω₂ = I₁ X ω₁ / I₂
Putting the values

ω₂ = 4.365 rad s⁻¹
c ) Increase in rotational kinetic energy
=1/2 I₂ X ω₂² - 1/2 I₁ X ω₁²
.5 X 256.25 X 4.365² - .5 X 356.25 X 3.14²
= 684.95 J
This energy comes from work done against the centripetal pseudo -force.
Answer:
B C & D
Explanation:
should make you money, time well spent no time lost.
Answer:
the net force on the object is 6 N.
Explanation:
Given;
force applied to the right on the object,
= 16 N
force applied to the left of the object,
= 16 N
force applied downward on the object,
= 6 N
The net horizontal force on the object = 
The net vertical force on the object = 
The net force on the object is calculated as;

Therefore, the net force on the object is 6 N.