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Gnesinka [82]
4 years ago
7

How much heat is needed to melt a 3 kg block of cheddar cheese initially at room tmperature of 24 degrees C? (assume the melting

point of cheddar cheese is 150 degrees C, the latent heat of fusion of cheese is 124 KJ/kg and the specific heat of cheddar cheese is 2.08 KJ/kg C)
Physics
1 answer:
Mnenie [13.5K]4 years ago
8 0

Cheese I'm so sorry for not having an answer I failed you

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Alex swims at an average speed of 45 m/min.how far does he swim in 1min 24 sec?
Drupady [299]

Answer: 72m/1 min and 24 secs

Explanation:

He swims .75m/sec. im pretty sure i got it but let me know and ill help you out if its wrong

8 0
3 years ago
Please help me in science plss​ <br><br><br>I give brainliest to Answer this plss
Elenna [48]
Stan looga
this is correct answer
8 0
3 years ago
A falling object is said to reach a constant velocity (terminal velocity)..
Lana71 [14]
C

Terminal velocity is the maximum velocity attainable by an object as it falls through a fluid (air is the most common example). It occurs when the sum of the drag force (Fd) and the buoyancy is equal to the downward force of gravity (FG) acting on the object.(Wikipedia)




3 0
3 years ago
8. Ella wants to replace old bulbs of her home with new LED bulbs. She buys LED bulb that has inbuilt AC to DC converter of outp
tankabanditka [31]

The power dissipated by the LED is 20 Watts and the work done for 1 hour 15 minutes is 56.25 kJ.

<h3>What is electrical power?</h3>

Electrical power is the rate at which electrical work is done.

  • Electrical power = voltage × current

The LED is 75% efficient means that 75% of power dissipated by the LED is converted to light.

Total power dissipated = 5 × 2.5 = 12.5 Watts

  • Work done = power × time (in seconds)

Work done = 12.5 × (1 × 3600 + 15 × 60)

Work done = 56250 J = 56.25 kJ

Therefore, the power dissipated by the LED is 20 Watts and the work done for 1 hour 15 minutes is 56.25 kJ.

Learn more about electrical power and work done at: brainly.com/question/23901751

#SP1

3 0
2 years ago
What is the average velocity of atoms in 1.00 mol of neon (a monatomic gas) at 465 K? For m, use 0.0202 kg.
TiliK225 [7]

Answer: 757m/s

Explanation:

Given the following :

Mole of neon gas = 1.00 mol

Temperature = 465k

Mass = 0.0202kg

Using the ideal gas equation. For calculating the average kinetic energy molecule :

0.5(mv^2) = 3/2 nRt

Where ;

M = mass, V = volume. R = gas constant(8.31 jK-1 mol-1, t = temperature in Kelvin, n = number of moles

Plugging our values

0.5(0.0202 × v^2) = 3/2 (1 × 8.31 × 465)

0.0101 v^2 = 5796.225

v^2 = 5796.225 / 0.0101

v^2 = 573883.66

v = √573883.66

v = 757.55109m/s

v = 757m/s

5 0
4 years ago
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