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Shtirlitz [24]
3 years ago
5

A car travels 60 miles in the first 2 hours and 68 miles in the next 2 hours

Physics
1 answer:
Gemiola [76]3 years ago
6 0

32miles/hr

Explanation:

Given parameters:

Distance 1 = 60miles

Time 1 = 2hrs

Distance 2 = 68miles

Time 2 = 2hrs

Unknown:

Average speed of the car =  ?

Solution:

Average speed is the total distance covered in a particular duration of time.

   Average speed = \frac{total distance}{total time taken}

 Total time taken = time 1 + time 2 = 2hrs + 2hrs = 4hrs

  Total distance = distance 1 + distance 2 = 60miles + 68miles = 128miles

Average speed = \frac{128miles}{4hrs} = 32miles/hr

learn more:

Motion brainly.com/question/2863017

#learnwithBrainly

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vladimir2022 [97]

Answer:

B: False

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A linear accelerator produces a pulsed beam of electrons. The pulse current is 0.50 A, and the pulse duration is 0.10 μs. (a) Ho
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Answer:

a)N = 3.125 * 10¹¹

b) I(avg)  = 2.5 × 10⁻⁵A

c)P(avg) = 1250W

d)P = 2.5 × 10⁷W

Explanation:

Given that,

pulse current is 0.50 A

duration of pulse Δt = 0.1 × 10⁻⁶s

a) The number of particles equal to the amount of charge in a single pulse divided by the charge of a single particles

N = Δq/e

charge is given by Δq = IΔt

so,

N = IΔt / e

N = \frac{(0.5)(0.1 * 10^-^6)}{(1.6 * 10^-^1^9)} \\= 3.125 * 10^1^1

N = 3.125 * 10¹¹

b) Q = nqt

where q is the charge of 1puse

n = number of pulse

the average current is given as I(avg) = Q/t

I(avg) = nq

I(avg) = nIΔt

         = (500)(0.5)(0.1 × 10⁻⁶)

         = 2.5 × 10⁻⁵A

C)  If the electrons are accelerated to an energy of 50 MeV, the acceleration voltage must,

eV = K

V = K/e

the power is given by

P = IV

P(avg) = I(avg)K / e

P(avg) = \frac{(2.5 * 10^-^5)(50 * 10^6 . 1.6 * 10^-^1^9)}{1.6 * 10^-^1^9}

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P = 2.5 × 10⁷W

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Answer:

54,000

Explanation:

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On the graph of voltage versus current, which line represents a 2.0 Ω resistor?​
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Answer:

<h2>line B</h2>

Explanation:

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Well it does carry blood and oxygen! Sorry but I'm not sure about 2 and 4.
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