Uh sure if you give me the problem I could help
Answer:
14.2
Step-by-step explanation:
Answer:
Use the graph to write a linear function that relates y to x. The points lie on a line. Find the slope and y-intercept of the line. Because the line crosses the y-axis at (0, −3), the y-intercept is −3.w
Step-by-step explanation:
There are three standard forms for linear functions y = f(x):
f(x) = mx + b (The "slope-intercept" form),
y - yo = m(x - x0) or, equivalently, f(x) = y0 + m(x - x0) (The "point-slope" or "Taylor" form), and.
Ax + By = C (The "general form") which defines y implicitly as a function of x as long as B 0.
Which of the following groups of numbers are all prime numbers? A. 3, 11, 23, 31 B. 2, 3, 5, 9 C. 2, 5, 15, 19 D. 7, 17, 29, 49
Mekhanik [1.2K]
A because 9 is not prime in answer B, 15 is not prime in answer C, and 49 is not prime in answer D. So the correct answer is A.
Short AnswerThere are two numbers
x1 = -0.25 + 0.9682i <<<<
answer 1x2 = - 0.25 - 0.9582i <<<<
answer 2 I take it there are two such numbers.
Let one number = x
Let one number = y
x + y = -0.5
y = - 0.5 - x (1)
xy = 1 (2)
Put equation 1 into equation 2
xy = 1
x(-0.5 - x) = 1
-0.5x - x^2 = 1 Subtract 1 from both sides.
-0.5x - x^2 - 1 = 0 Order these by powers
-x^2 - 0.5x -1 = 0 Multiply though by - 1
x^2 + 0.5x + 1 = 0 Use the quadratic formula to solve this.

a = 1
b = 0.5
c = 1

x = [-0.5 +/- sqrt(0.25 - 4)] / 2
x = [-0.5 +/- sqrt(-3.75)] / 2
x = [-0.25 +/- 0.9682i
x1 = -0.25 + 0.9682 i
x2 = -0.25 - 0.9682 i
These two are conjugates. They will add as x1 + x2 = -0.25 - 0.25 = - 0.50.
The complex parts cancel out. Getting them to multiply to 1 will be a little more difficult. I'll do that under the check.
Check(-0.25 - 0.9682i)(-0.25 + 0.9682i)
Use FOIL
F:-0.25 * -0.25 = 0.0625
O: -0.25*0.9682i
I: +0.25*0.9682i
L: -0.9682i*0.9682i = - 0.9375 i^2 = 0.9375
NoticeThe two middle terms (labled "O" and "I" ) cancel out. They are of opposite signs.
The final result is 0.9375 and 0.0625 add up to 1