Answer:
Moles of carbon dioxide gas is 0.584 moles.
Mass of 0.584 moles of carbon dioxide gas is 25.7 g
Explanation:
Using ideal gas equation
PV = nRT
where,
P = Pressure of gas = 
V = Volume of gas = 30.0 L
n = number of moles of gas = ?
R = Gas constant = 0.0821 L.atm/mol.K
T = Temperature of gas = 27°C = 300.15 K
Putting values in above equation, we get:

Moles of carbon dioxide gas = 0.584 moles
Mass of 0.584 moles of carbon dioxide gas = 0.584 mol × 44 g/mol = 25.69 g ≈ 25.7 g
Answer:
The mole and atonmicity of both the gases are different, the number of atoms is not same.
Explanation:
The number of atoms in a molecule (compound) depends on mole number and atomicity.
↬ Mole of 100 g H₂ = 100g ÷ 2u = 50 mole
∴Number of atoms in 100 g H₂
= 2 x 50 x 6.022 × 10²³
= 6.022 x 10²⁴ atoms
↬ Mole of 100 g He = 100g ÷ 4u = 25 mole
∴ Number of atoms in 100 g He
= 1 × 25 × 6.022 × 10²³
= 150.55 × 10²³
= 1.5055 x 10²⁵ atoms
Thus, The mole and atonmicity of both the gases are different, the number of atoms is not same.
<u>-TheUnknownScientist</u><u> 72</u>
The ionization constant equation is:
=1.0 ×
at 25°C
the option is 1.
Explanation:
Sometimes in pure water one proton of the water molecule(hydrogen ion) will get attracted to the lone pairs present in another water molecule.This causes the hydrogen ion to leave the present water(leaving the
behind) molecule ad gets attached to another water molecule leading to the formation of the hydronium ion(
,hydronium ion).
This process is called auto-ionization of water because the water molecule ionizes into
and
ions.
<h2>

<u>
+</u>

<u>
→</u>

<u>
+ </u>

</h2>
As such the equilibrium constant,which is measure of concentration of products to concentration of reactants,will be very slow.
∴the ionization constant of water at 25°C is 1.0 ×
.
(i.e.)option<u> c</u> is correct answer [
]=[
]