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3 years ago

Which type of stoichiometry problems does not require the use of molar mass?

Chemistry

1 answer:

Arlecino [84]3 years ago

7 0

Answer:

Explanation:

It is volume-volume problems that does not require the use of molar mass.

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In the engineering design process what do engineers do immediately after testing a prototype

mote1985 [20]

Answer:

Iterate to improve the solution

Explanation:

apex

5 0

3 years ago

30cm^3 of a dilute solution of Ca(OH)2 required 11 cm^3 of 0.06 mol/dm^. Hcl for complete neutralization. Calculate the concentr

Alenkasestr [34]

Answer: Thus concentration of $Ca(OH)_2$ in $mol/dm^3$ is 0.011 and in $g/dm^3$ is 0.814

Explanation:

To calculate the concentration of $Ca(OH)_2$ , we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is $Ca(OH)_2$

We are given:

$n_1=1\\M_1=0.06mol/dm^3\\V_1=11cm^3=0.011dm^3\\n_2=2\\M_2=?\\V_2=30cm^3=0.030dm^3$ $1cm^3=0.001dm^3$

Putting values in above equation, we get:

$1\times 0.06mol/dm^3\times 0.011dm^3=2\times M_2\times 0.030dm^3\\\\M_2=0.011mol/dm^3$

The concentration in $g/dm^3$ is $0.011mol/dm^3\times 74g/mol=0.814g/dm^3$

Thus concentration of $Ca(OH)_2$ is $0.011mol/dm^3$ and $0.814g/dm^3$

4 0

3 years ago

What is the oxidation state of Hg in Hg2Cl2?

Anna [14]

Answer:

Explanation:

Electrochemistry. In oxidation–reduction (redox) reactions, electrons are transferred from one A redox reaction is balanced when the number of electrons lost by the reductant Hg(l)∣Hg2Cl2(s)∣Cl−(aq) ∥ Cd2+(aq)∣Cd(s).

As is evident from the Stock number, mercury has an oxidation state of +1. This makes sense, as chlorine usually has an oxidation state of -1.

5 0

3 years ago

You decide you want to carry a boulder home from the beach. It is 20 centimeters on each

e-lub [12.9K]

Answer:

Weight of boulder = 22,400 gram

Explanation:

Given:

Volume = 8,000 cm³

Density = 2.8

Find:

Weight of boulder

Computation:

Weight of boulder = Volume x Density

Weight of boulder = 8,000 x 2.8

Weight of boulder = 22,400 gram

3 0

3 years ago

Which area of chemistry best links the use of titanium and plastics in artificial bone and joint replacements?

kogti [31]

Answer:I think it’s material chemistry

Explanation:

8 0

3 years ago