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zloy xaker [14]
3 years ago
14

HELP When 400 J of heat is added to 5.6 g of olive oil at 23*C, the temperature increases to 87*C. What is the specific heat of

the olive oil? (Show all work including the equation you use to solve). (3 points).
Chemistry
1 answer:
babunello [35]3 years ago
4 0

Q=mc*temperature change

400=5.6/1000*c*(87-23)

c=1160.07J/kg/k

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Maurinko [17]
1.) Na
2.) Cl ( at the second blank)
sodium metal+hydrochloric acid
3 0
3 years ago
A 508-g sample of sodium bicarbonate (NaHCO3) contains how many moles of sodium bicarbonate (NaHCO3)?
Blizzard [7]

molar mass = (22.99) + (1.01) + (12.01) + 3(16.00)

molar mass = 84.01 g/mol

//

(508g)(1 mol/84.01 g) = 6.0

There are 6.0 moles of sodium bicarbonate

3 0
3 years ago
1. Which of the following is NOT a cation?
Bezzdna [24]
Hey Madoudou


The correct answer is option B (sulfate)


The reason is because "Sulfate" has a negative sign.

In order for it to be a cation, it must have positive sign such as "iron(lll)ion


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3 0
3 years ago
Please help me with this chemistry
kobusy [5.1K]

Answer:

57)a)increase

b)increase

c)pressure

58)

7 0
2 years ago
At its critical point, ammonia has a density of 0.235 g cm23. You have a special thick­walled glass tube that has a 10.0­mm outs
salantis [7]

Answer:

\large \boxed{\text{69.3 mg}}

Explanation:

1. Volume of sealed tube

Assume the sealed tube is a right circular cylinder in which the cap and the base are also 4.20 mm thick.

Its outside dimensions are 155 mm long × 10.0 mm diameter.

Its inside dimensions are

h = 155 mm - 2 × 4.20 mm = 146.6 mm

r = 5.0 mm - 4.20 mm = 0.8 mm

V = πr²h = π(0.8)²× 146.6 mm³ = 294.8 mm³ = 0.2948 cm³

2. Calculate the mass of NH₃

\begin{array}{rcl}\text{Density} & = & \dfrac{\text{Mass}}{\text{Volume}}\\\\\rho & = &\dfrac{m}{V}\\\\0.235 \text{ g$\cdot$ cm}^{-3} & = & \dfrac{m}{\text{0.2948 cm}^{3}}\\\\m & = & \text{0.0693 g}\\& = & \textbf{69.3 mg}\\\end{array}\\\text{You must seal $\large \boxed{\textbf{69.3 mg}}$ of ammonia in the tube.}

4 0
3 years ago
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