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lina2011 [118]
3 years ago
9

The point (0,5) lies on a circle that is centered at the

Mathematics
1 answer:
sergey [27]3 years ago
5 0

Answer:5,5,yes

Step-by-step explanation:

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A certain pickup truck gets 20mpg in the city and 28 mpg on the highway. If the driver drives 270 mi on 11 gal of gas, determine
Snezhnost [94]

Answer:

95 city and 175 highway miles.

Step-by-step explanation:

The driver gets 20 mpg in city, and 28 mpg on the highway.

An equation that could be written is

20x+28y=270

This equation accounts for the distance traveled.

x+y=11

This equotion accounts for how many gallons were driven.

Multiply the bottom equation by 20, so you can solve the set of equations.

20x+28y=270

20x+20y=220

subtract them

8y=50

y=6.25

now plug this back into x+y=11

x+6.25=11

x=4.75

Now 4.75×20=95 city miles and 6.25×28=175 highway miles.

8 0
3 years ago
93000000 in standard form
noname [10]
It’s already in standard form: 93,000,000

If we would put it in scientific notation though, it would be: 9.3 x10 ^7 (to the power of 7)
3 0
3 years ago
A gas tank has a leak. Each hour it loses 3 gallons of gas. Write the equation that represents how much gas, g , the tank loses
zhenek [66]
Let t is the amount of time that the gas is leaking (hour), g is the total of the gas leak.

g = 3t. 
7 0
3 years ago
How to solve this equation 7-2a-5-14=-2+3a
SSSSS [86.1K]

To solve 7-2a-5-14=-2+3a :

1) combine like terms: 7-19 - 2a = -2 + 3a, and then -10 = 5a

2) solve this equation for a: a = -10/5 = -2.

The solution of 7-2a-5-14=-2+3a is a = -2.

6 0
3 years ago
Read 2 more answers
Does the series converge or diverge? If it converges, what is the sum? Show your work. ∑ ∞ n = 1 − 4 ( − 1 / 2 ) n − 1
Mekhanik [1.2K]

Answer:

Step-by-step explanation:

Given the series,

∑ ∞ n = 1 − 4 ( − 1 / 2 ) n − 1

I think the series is summation from n = 1 to ∞ of -4(-1/2)^(n-1)

So,

∑ − 4 ( − ½ )^(n − 1). From n = 1 to ∞

There are different types of test to show if a series converges or diverges

So, using Ratio test

Lim n → ∞ (a_n+1 / a_n)

Lim n → ∞ (-4(-1/ 2)^(n+1-1) / -4(-1/2)^(n-1))

Lim n → ∞ ((-4(-1/2)^(n) / -4(-1/2)^(n-1))

Lim n → ∞ (-1/2)ⁿ / (-1/2)^(n-1)

Lim n→ ∞ (-1/2)^(n-n+1)

Lim n→ ∞ (-1/2)^1 = -1/2

Since the limit is less than 0, then, the series converge...

Sum to infinity

Using geometric progression formula

S∞ = a / 1 - r

Where

a is first term

r is common ratio

So, first term is

a_1 = -4(-½)^1-1 = -4(-½)^0 = -4 × 1

a_1 = -4

Common ratio r = a_2 / a_1

a_2 = 4(-½)^2-1 = -4(-½)^1 = -4 × -½ = 2

a_2 = 2

Then,

r = a_2 / a_1 = 2 / -4 = -½

S∞ = -4 / 1--½

S∞ = -4 / 1 + ½

S∞ = -4 / 3/2 = -4 × 2 / 3

S∞ = -8 / 3 = -2⅔

The sum to infinity is -2.67 or -2⅔

Check attachment for better understanding

3 0
3 years ago
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