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3 years ago

The point (0,5) lies on a circle that is centered at the

Mathematics

1 answer:

sergey [27]3 years ago

5 0

Answer:5,5,yes

Step-by-step explanation:

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Show 2-(-3) on a number line.

9966 [12]

Just put a closed circle above 5 on the # line.

3 0

2 years ago

Solve each system of equations. 2x + 3y = 3 3x + 5y = 6 o (4,1) Ob (0,1) (-3,3) Od (3-4)

Sergeu [11.5K]

Answer:

x = 3 n, y = -2 n, n element Z

Step-by-step explanation:

3 0

2 years ago

4 - x + <img src="https://tex.z-dn.net/?f=6%5E%7B2%7D" id="TexFormula1" title="6^{2}" alt="6^{2}" align="absmiddle" class="latex

Lemur [1.5K]

Answer:

x ≤ 19

Step-by-step explanation:

The instructions here are probably "solve for x." Please include them.

4 - x + 6^2 ≥ 21

becomes 4 - x + 36 ≥ 21

Now combine like terms. 4 and 36 combine to 40: 40 - x ≥ 21, and so:

19 - x ≥ 0

Adding x to both sies results in

x ≤ 19

Please, include the instructions when you post a question. Thanks.

3 0

2 years ago

A combined total of $46,000 is invested in two bonds that pay 4% and

valkas [14]

Answer: 4%-16000 and 9.5%-30000

Why:

1) x+y=46000

x=46000-y

2) 4%x+9,5%y=3490;

4x + 9.5y=349000; so 4*(46000-y)+9.5y=349000;

5.5y=165000

y=30000

x=46000-30000=16000

5 0

3 years ago

Would you need to use the chain rule to find the derivative of this function?

Nutka1998 [239]

Answer:

TRUE. We need to use the chain rule to find the derivative of the given function.

Step-by-step explanation:

Chain rule to find the derivative,

We have to find the derivative of F(x)

If F(x) = f[g(x)]

Then F'(x) = f'[g(x)].g'(x)

Given function is,

y = $\sqrt{2x+3}$

Here g(x) = (2x + 3)

and f[g(x)] = $\sqrt{2x+3}$

$\frac{dy}{dx}=\frac{d}{dx}(\sqrt{2x+3}).\frac{d}{dx} (2x+3)$

y' = $\frac{1}{2}(2x+3)^{(1-\frac{1}{2})}.(2)$

= $(2x+3)^{-\frac{1}{2}}$

y' = $\frac{1}{\sqrt{2x+3}}$

Therefore, it's true that we need to use the chain rule to find the derivative of the given function.

8 0

3 years ago