The point (0,5) lies on a circle that is centered at the

A bakery sells 9 vanilla cakes for every 5 chocolate cakes. This is represented in the diagram below. Use the drop-down menus to

Dmitrij [34]

Step-by-step explanation:

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5 0

3 years ago

Read 2 more answers

13 POINTS- please help me

allsm [11]

Answer:

See explanation

Step-by-step explanation:

16. Two parallel lines are cut by transversal. Angles with measures $(6x+20)^{\circ}$ and $(x+100)^{\circ}$ are alternate exterior angles. By alternate exterior angles, the measures of alternate exterior angles are the same:

$6x+20=x+100\\ \\6x-x=100-20\\ \\5x=80\\ \\x=16$

Then

$(6x+20)^{\circ}=(6\cdot 16+20)^{\circ}=116^{\circ}\\ \\(x+100)^{\circ}=(16+100)^{\circ}=116^{\circ}$

17. Two parallel lines are cut by transversal. Angles with measures $(2x+12)^{\circ}$ and $(3x-22)^{\circ}$ are alternate interior angles. By alternate interior angles, the measures of alternate interior angles are the same:

$2x+12=3x-22\\ \\2x-3x=-22-12\\ \\-x=-34\\ \\x=34$

Then

$(2x+12)^{\circ}=(2\cdot 34+12)^{\circ}=80^{\circ}\\ \\(3x-22)^{\circ}=(3\cdot 34-22)^{\circ}=80^{\circ}$

18. Two parallel lines are cut by transversal. Angles with measures $(6x-7)^{\circ}$ and $(5x+10)^{\circ}$ are alternate exterior angles. By alternate interior angles, the measures of alternate exterior angles are the same:

$6x-7=5x+10\\ \\6x-5x=10+7\\ \\x=17$

Then

$(6x-7)^{\circ}=(6\cdot 17-7)^{\circ}=95^{\circ}\\ \\(5x+10)^{\circ}=(5\cdot 17+10)^{\circ}=95^{\circ}$

19. The diagram shows two complementary angles with measures $2x^{\circ}$ and $56^{\circ}$ . The measures of complementary angles add up to $90^{\circ},$ then

$2x+56=90\\ \\2x=90-56\\ \\2x=34\\ \\x=17$

Hence,

$2x^{\circ}=2\cdot 17^{\circ}=34^{\circ}$

Check:

$34^{\circ}+56^{\circ}=90^{\circ}$

20. Angles $\angle 1$ and $\angle 2$ are vertical angles. By vertical angles theorem, vertical angles are congruent, so

$m\angle 1=m\angle 2\\ \\5x+7=3x+15\\ \\5x-3x=15-7\\ \\2x=8\\ \\x=4$

Hence,

$m\angle 1=(5x+7)^{\circ}=(5\cdot 4+7)^{\circ}=27^{\circ}\\ \\m\angle 2=(3x+15)^{\circ}=(3\cdot 4+15)^{\circ}=27^{\circ}$

21. $\angle 5$ and $\angle 8$ are supplementary. The measures of supplementary angles add up to $180^{\circ},$ so

$m\angle 5+m\angle 8=180^{\circ}\\ \\3x-40+7x-120=180\\ \\10x-160=180\\ \\10x=180+160\\ \\10x=340\\ \\x=34$

Therefore,

$m\angle 5=(3x-40)^{\circ}=(3\cdot 34-40)^{\circ}=62^{\circ}\\ \\m\angle 8=(7x-120)^{\circ}=(7\cdot 34-120)^{\circ}=118^{\circ}\\ \\62^{\circ}+118^{\circ}=180^{\circ}$

7 0

3 years ago

What is the slope of the line that contains the points (-3,5)and (-5,6)

tigry1 [53]

(-3,5) (-5,6)
slope = 5-6 / -3 --5
slope = -1 / 2

6 0

3 years ago

How much more is 3 1/4 than 1 3/4

Stels [109]

Answer:

1 and 1/2

Step-by-step explanation:

3 1/4 is equal to 13/4 and 1 3/4 is equal to 7/4. 13/4 - 7/4 is 6/4. 6/4 equalsn is 1 1/2.

4 0

3 years ago

There is a line that includes the point(10, 5)and has a slope of 1 What

ziro4ka [17]

Answer:

y = x - 5

Step-by-step explanation:

Given the point, (10, 5), and the slope, m = 1:

Substitute these values into the slope-intercept form to solve for the y-intercept, b:

y = mx + b

5 = 1(10) + b

5 = 10 + b

Subtract 10 from both sides to isolate b:

5 - 10 = 10 - 10 + b

-5 = b

The y-intercept of the line is: b = -5. This represents the y-coordinate of the y-intercept, (0, -5), which represents the point on the graph where it crosses the y-axis. Along the y-axis, the value of x = 0. Hence, the y-intercept is (0, -5).

Therefore, given the slope, m = 1, and the y-intercept, b = -5:

The equation of the line in slope-intercept form is: y = x - 5.

3 0

3 years ago